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Radda [10]
2 years ago
12

Read the following chemical equations.

Chemistry
1 answer:
lora16 [44]2 years ago
8 0

This problem is providing two reduction-oxidation (redox) reactions in which the oxidized and reduced species can be identified by firstly setting the oxidation number of each element:

Reaction 1: 2K⁺I⁻ + H₂⁺O₂⁻  ⇒2K⁺O⁻²H⁺ + I₂⁰

Reaction 2: Cl₂⁰ + H₂⁰ ⇒ 2H⁺CI⁻

Next, we can see that iodine is being oxidized and oxygen reduced in reaction #1 and chlorine is being reduced and hydrogen oxidized in reaction #2 because the oxidized species increase the oxidation number whereas the reduced ones decrease it.

In such a way, the correct choice is C.

Learn more:

  • (Redox reactions) brainly.com/question/13978139

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Balance the following chemical equation: <br> ___HCO + ___O —&gt; ___H2 + ___CO3
yawa3891 [41]

Answer: 2HCO + 4O → H2 + 2CO3

Explanation: Oxomethyl + Oxygen = Dihydrogen + Carbon Trioxide

Reaction Type: SINGLE REPLACEMENT

***If you found my answer helpful, please give me the brainliest, please give a nice rating, and the thanks ( heart icon :) ***

7 0
2 years ago
Mercury’s natural state is where the atoms are close to each other but are still free to pass by each other. In which state(s) c
kvv77 [185]

Mercury naturally exists in Liquid state.

On Condensing it can exist in Solid state as well.

Hope it helps...

Regards;

Leukonov/Olegion.

3 0
3 years ago
Read 2 more answers
What is an indication that a lake is healthy?
N76 [4]

Answer:

D

Explanation:

As bioindicators are the organism that indicate or monitor the health of the environment

7 0
3 years ago
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What type of radioactive decay will the isotopes 13B and 188Au most likely undergo?
scoundrel [369]

Answer:

b. Beta emission, beta emission

Explanation:

A factor to consider when deciding whether a particular nuclide will undergo this or that type of radioactive decay is to consider its neutron:proton ratio (N/P).

Now let us look at the N/P ratio of each atom;

For B-13, there are 8 neutrons and five protons N/P ratio = 8/5 = 1.6

For Au-188 there are 109 neutrons and 79 protons N/P ratio = 109/79=1.4

For B-13, the N/P ratio lies beyond the belt of stability hence it undergoes beta emission to decrease its N/P ratio.

For Au-188, its N/P ratio also lies above the belt of stability which is 1:1 hence it also undergoes beta emission in order to attain a lower N/P ratio.

8 0
2 years ago
According to the VSEPR model, the arrangement of electron pairs around NH3 and CH4 is A. the same, because in each case there ar
aleksklad [387]

Answer:

Option "B" is correct.

Explanation:

According to VSEPR theory, There are repulsion forces exists among the bond pair - bond pair or bond pair - lone pair of electrons. In NH_{3} and  CH_{4}, the number of electron pairs are same but methane has all the four bond pairs where in ammonia, three bond pairs and one lone pair exists. And thus there are repulsion forces possible in between the lone pair and bond pair of electrons thus the arrangement of electron pairs around both the molecules is same or different depending up on the conditions leading to maximum repulsion.  

3 0
3 years ago
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