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Vika [28.1K]
3 years ago
12

A 50.0-g sample of liquid water at 25.0 °c is mixed with 23.0 g of water at 79.0 °c. the final temperature of the water is ___

_____ °c.
Chemistry
1 answer:
I am Lyosha [343]3 years ago
8 0

<span><span>m1</span>Δ<span>T1</span>+<span>m2</span>Δ<span>T2</span>=0</span>

<span><span>m1</span><span>(<span>Tf</span>l–l<span>T<span>∘1</span></span>)</span>+<span>m2</span><span>(<span>Tf</span>l–l<span>T<span>∘2</span></span>)</span>=0</span>

<span>50.0g×<span>(<span>Tf</span>l–l25.0 °C)</span>+23.0g×<span>(<span>Tf</span>l–l57.0 °C)</span>=0</span>

<span>50.0<span>Tf</span>−1250 °C+23.0<span>Tf</span> – 1311 °C=0</span>

<span>73.0<span>Tf</span>=2561 °C</span>

<span><span>Tf</span>=<span>2561 °C73.0</span>=<span>35.1 °C</span></span>

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A 4.0 L balloon has a pressure of 406 kPa. When the pressure increases to 2,030 kPa, what is the volume? *
elena-14-01-66 [18.8K]

The new volume when pressure increases to 2,030 kPa is 0.8L

BOYLE'S LAW:

The new volume of a gas can be calculated using Boyle's law equation:

P1V1 = P2V2

Where;

  1. P1 = initial pressure (kPa)
  2. P2 = final pressure (kPa)
  3. V1 = initial volume (L)
  4. V2 = final volume (L)

According to this question, a 4.0 L balloon has a pressure of 406 kPa. When the pressure increases to 2,030 kPa, the volume is calculated as:

406 × 4 = 2030 × V2

1624 = 2030V2

V2 = 1624 ÷ 2030

V2 = 0.8L

Therefore, the new volume when pressure increases to 2,030 kPa is 0.8L.

Learn more about Boyle's law calculations at: brainly.com/question/1437490?referrer=searchResults

3 0
3 years ago
What is the value for (delta)G at 1000 K if (delta)H = -220 kJ/mol and (delta)S = -0.05 kJ/(molK)?
tankabanditka [31]
The system is isothermal, so we use the formula:
(delta)G = (delta)H - T (delta) S

Plugging in the given values:
(delta)G = -220 kJ/ mol - (1000K) (-0.05 kJ/mol K)
(delta)G = -170 kJ/mol

If we take a basis of 1 mol, the answer is
D. -170 kJ 
6 0
3 years ago
Read 2 more answers
Selective Uptake and Gas Transport in Chemically Modified PIMs
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Selective uptake is the procedure with the aid of using which membranes in cells decide what molecules can cross in and what molecules can exit of a cell.

The studies aimed to expand chemically changed PIM-1s to be used in adsorption and fueloline separation processes. In particular, the nitrile institution in PIM-1 became transformed to numerous one of a kind purposeful organizations to control the interplay capacity of PIM-1 with one of a kind species. Synthesis of PIM-1 became done with the aid of using one of a kind methods, the usage of each the low (72h, 65 °C) and the excessive temperature (forty min, 160 °C) methods.

The response led to a aggregate of hydrolysis products. The composition of the polymer has a profound impact at the very last overall performance of the polymer. Powder samples of hydrolysed PIMs had been used withinside the studies. The discount of nitrile to number one amine became done the usage of borane dimethyl sulphide complex, ensuing in amine PIM-1.

Read more about transport;

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3 0
2 years ago
2 icl + h2i2 + 2 hcl is first order in icl and second order in h2. Complete the rate law for this reaction in the box below. Use
OleMash [197]

2 ICl + H2   ----> I2 + 2 HCl

as given that rate is first order with respect to ICl and second order with respect to H2

The rate law will be

Rate = K [ICl] [ H2]^2

b) Given that K = 2.01 M^-2 s^-1

Concentrations are

[ICl] = 0.273 m and [H2] = 0.217 m

Therefore rate = 2.01 X (0.273)(0.217)^2 = 0.0258 M / s

5 0
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A. It can be as important to a story as a character
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