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Eduardwww [97]
3 years ago
13

On what frequency can you expect to monitor air traffic in and around Lincoln Airport?

Engineering
1 answer:
Phantasy [73]3 years ago
5 0

Answer:

118.5

Explanation:

Hope this helps!

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What is meant by engineering jobs ​
Hoochie [10]

Answer:

Engineers work in a variety of fields to analyze, develop and evaluate large-scale, complex systems. This can mean and improve and maintaining current systems or creating brand new projects. Engineers will design and draft blueprints, visit systems in the field and manage projects.

4 0
3 years ago
Read 2 more answers
A compressor operates at steady state with Refrigerant 134a as the working fluid. The refrigerant enters at 0.24 MPa, 0°C, with
marissa [1.9K]

Answer:

POWER INPUT = 82.989 KW

Explanation:

For pressure P =0.24 MPa and T_1 = 0 DEGREE, Enthalapy _1 = 248.89 kJ/kg

For pressure P =1  MPa and T_1 = 50 DEGREE, Enthalapy _1 = 280.19 kJ/kg

Heat loss Q = 0.05w

Inlet diameter = 3 cm

exit diamter = 1.5  cm

volume of tank will be v = area * velocity

velocity at inlet= \frac{0.64\60 m/s}{ \frac{\pi}{4} (3\times 10^{-2})^2} = 15.09  m/s

velocity at outlet= \frac{0.64\60 m/s}{ \frac{\pi}{4} (1.5\times 10^{-2})^2} = 60.36  m/s

steady flow energy equation

E_{IN} = E_{OUT}

h_1 + \frac{v_1^2}{2g} +wc = h_2 + \frac{v_2^2}{2g} + 0.05wc

248.89 + \frac{15.09^2}{2} + wc = 280.18 + \frac{60.36^2}{2} + 0.05 wc

solving wc = 1830.64  kJ/kg

wc in KWH

we know thatwc = \dot m wc

       \dot m = 4.25 kg/m3 \times (0.64/60) m^3/s

\dot m = 0.04533  kg/s

wc = 0.04533 \times 1830.64 = 82.989 kW

5 0
4 years ago
Write an application that solicits and inputs three integers from the user and then displays the sum, average, product, smallest
Ganezh [65]

Answer:

3423=6^H

Explanation:

6 0
3 years ago
A rectangular block of material with shear modulus G= 620 MPa is fixed to rigid plates at its top and bottom surfaces. Thelower
PIT_PIT [208]

Answer:

γ_{xy} =0.01, P=248 kN

Explanation:

Given Data:

displacement = 2mm ;

height = 200mm ;

l = 400mm ;

w = 100 ;

G = 620 MPa = 620 N//mm²;    1MPa = 1N//mm²

a. Average Shear Strain:

The average shear strain can be determined by dividing the total displacement of plate by height

γ_{xy} = displacement / total height

     = 2/200 = 0.01

b. Force P on upper plate:

Now, as we know that force per unit area equals to stress

τ = P/A

Also,  τ = Gγ_{xy}

By comapring both equations, we get

P/A = Gγ_{xy}   ------------ eq(1)

First we need to calculate total area,

A = l*w = 400 * 100= 4*10^4mm²

By putting the values in equation 1, we get

P/40000 = 620 * 0.01

P = 248000 N or 2.48 *10^5 N or 248 kN

6 0
3 years ago
A state of stress that occurs at a point on the free surface of the of a solid body is = 50 MPa σ x , =10 MPa σ y , and = −15 MP
posledela

Answer:

A) 5 MPa , 55 MPa

B) maximum stress = 55 MPa,  maximum shear stress = 25 MPa

Explanation:

using the given Data

free surface of a solid body

α_{x} = 50 MPa,    α_{y} = 10 MPa , t_{xy} = -15 MPa

attached below is the detailed solution to the question

7 0
3 years ago
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