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7nadin3 [17]
2 years ago
15

Lab scale tests performed on a cell broth with a viscosity of 5cP gave a specific cake resistance of 1 x1011 cm/g and a negligib

le medium resistance. The cake solids (dry basis) per volume of filtrate was 20 g/liter. It is desired to operate a larger rotary vacuum filter (diameter 8 m and length 12 m) at a vacuum pressure of 80 kPA with a cake formation time of 20 s and a cycle time of 60 s. Determine the filtration rate in volumes/hr expected for the rotary vacuum filter.
Engineering
1 answer:
insens350 [35]2 years ago
4 0

Answer:

5.118 m^3/hr

Explanation:

Given data:

viscosity of cell broth = 5cP

cake resistance = 1*1011 cm/g

dry basis per volume of filtrate = 20 g/liter

Diameter = 8m ,  Length = 12m

vacuum pressure = 80 kpa

cake formation time = 20 s

cycle time = 60 s

<u>Determine the filtration rate in volumes/hr  expected fir the rotary vacuum filter</u>

attached below is a detailed solution of the question

Hence The filtration rate in volumes/hr expected for the rotary vacuum filter

V' = ( \frac{60}{20} ) * 1706.0670

   = 5118.201 liters  ≈ 5.118 m^3/hr

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ddd [48]

Answer:

//Annual calendar

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#include <string>

#include <iomanip>

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{

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// Header print

      cout << "\n----------------------\n";

      for(i=0; i<7; i++)

{

cout << left << setw(1) << weekDays[i];

cout << left << setw(1) << "|";

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cout << left << setw(1) << "|";

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      for(int i=1; i< firstDay; i++)

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      for(int i=1; i<=numDays; i++)

      {

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          if ((i + firstDay-1) % 7 == 0)

          {

              cout << left << setw(1) << "|";

              cout << "\n----------------------\n";

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          }

      }

      // Empty cell print

      if (cellCnt != 0)

      {

          // For printing spaces

          for(int i=1; i<7-cellCnt+2; i++)

              cout << left << setw(1) << "|" << setw(2) << " ";

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}

int main()

{

int i, day=1;

int yearly[12][2] = {{1,31},{2,28},{3,31},{4,30},{5,31},{6,30},{7,31},{8,31},{9,30},{10,31},{11,30},{12,31}};

string months[] = {"January",

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"March",

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"May",

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"July",

"August",

"September",

"October",

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for(i=0; i<12; i++)

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month(yearly[i][1], day);

if(day==7)

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day = 1;

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Answer:

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Explanation:

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State 2

P_2 =6bar\\T_2 = 296K\\T_f = 320K

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u_2 = 228.42kJ/kg

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3 years ago
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