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RoseWind [281]
3 years ago
10

Which statement did Kepler’s investigations of the movement of the planets explain?

Physics
2 answers:
wlad13 [49]3 years ago
7 0

Answer:

It’s the fourth one :)

Explanation:

Katen [24]3 years ago
3 0

Answer:

earth is not the center of the universe

Explanation:

i just took the test

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In class we calculated the range of a projectile launched on flat ground. Consider instead, a projectile is launched down-slope
zysi [14]

Answer:

With an initial speed of 10m/s at an angle 30° below the horizontal, and a height of 8m, the projectile travels 7.49m horizontally before it lands.

Explanation:

Since the horizontal motion is independent from the vertical motion, we can consider them separated. The horizonal motion has a constant speed, because there is no external forces in the horizontal axis. On the other hand, the vertical motion actually is affected by the gravitational force, so the projectile will be accelerated down with a magnitude g.

If we have the initial velocity v_o and its angle \theta, we can obtain the vertical component of the velocity v_{oy} using trigonometry:

v_{oy}=v_osin\theta

Therefore, if we know the height at which the projectile was launched, we can obtain the final velocity using the formula:

v_{fy}^{2} =v_{oy}^{2}+2gy\\\\ v_{fy}=\sqrt{v_{oy}^{2}+2gy }

Next, we compute the time the projectile lasts to reach the ground using the definition of acceleration:

g=\frac{v_{fy}-v_{oy}}{\Delta t} \\\\\Delta t= \frac{v_{fy}-v_{oy}}{g}=\frac{\sqrt{v_{oy}^{2}+2gy} -v_{oy}}{g}

Finally, from the equation of horizontal motion with constant speed, we have that:

x=v_{ox}\Delta t= v_{ox}\frac{\sqrt{v_{oy}^{2}+2gy} -v_{oy}}{g}

For example, if the projectile is launched at an angle 30° below the horizontal with an initial speed of 10m/s and a height 8m, we compute:

v_{ox}=10\frac{m}{s} cos30=8.66\frac{m}{s}\\v_{oy}=10\frac{m}{s} sin30=5\frac{m}{s}\\\\x=8.66\frac{m}{s} \frac{\sqrt{(5\frac{m}{s}) ^{2}+2(9.8\frac{m}{s^{2}})8m}-5\frac{m}{s}  }{9.8\frac{m}{s^{2} } } =7.49m

In words, the projectile travels 7.49m horizontally before it lands.

8 0
4 years ago
If you could travel from one planet to another
marin [14]
The answer is A. Mass is constant, height and width won’t change. So that leaves weight.
7 0
4 years ago
Read 2 more answers
It takes 50.0 J to push a large box 4.00 m across a floor. Assuming the push is in the same direction as the move, what is the m
Blababa [14]
<h3><u>Answer;</u></h3>

12.5 Newtons

<h3><u>Explanation;</u></h3>

Work done is defined as the product of force and distance covered or moved. It is measured in joules.

Work done = Force × distance

Therefore; making force the subject;

Force = work done/distance

         = 50.0 J/ 4.00 m

         =<u> 12.5 Newtons.</u>

8 0
3 years ago
When a hypothesis is wrong, scientists often begin by revising the (blank)
Vsevolod [243]
I might be wrong, but. The words seem to fit. 

When a hypothesis is wrong, scientists often begin by revising the question after that, its common for scientists to redesign the experiment.
7 0
3 years ago
Read 2 more answers
Let’s say you pour an ounce of water from a class into a bowl. Does the water’s mass change?
ch4aika [34]

Answer:

No. If you take 5$ from your wallet and place on the shelf, does it change its value - No. So if you take the water from class(does not matter how much) and pour all of it somewhere else, it doesn't change its mass, yet it changes its shape.

5 0
3 years ago
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