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Cerrena [4.2K]
3 years ago
10

The resistance of physiological tissues is quite variable. The resistance of the internal tissues of humans, primarily composed

of salty solutions, is quite low. Here the resistance between two internal points in the body is on the order of 100 ohms. Dry skin, however, can have a very high resistance, with values ranging from thousands to hundreds of thousands of ohms. However, if skin is wet, it is far more conductive, and so even contact with small voltages can create large, dangerous currents though a human body. (For example, although there is no specific minimum current that is lethal, currents generally exceeding a couple tenths of Amps may be deadly.)
Assuming that electrocution can be prevented if currents are kept below 0.1 A, and assuming the resistance of dry skin is 100,000 ohms, what is the maximum voltage with which a person could come into contact while avoiding electrocution? (Of course, all bets are off and things become far more dangerous if this person's skin is wet, which can reduce the resistance by more than a factor of 100.)
Physics
1 answer:
irga5000 [103]3 years ago
4 0

Given Information:  

Current = I = 0.1 A

Resistance = R = 100 kΩ

Required Information:  

Voltage = V = ?

Answer:  

Voltage = V = 1000 V

Step-by-step explanation:  

We know that electrocution depends upon the amount of current flowing through the body and the voltage across the body.

V = IR

Where I is the current flowing through the body and R is the resistance of body.

If electrocution can be avoided when the current is below 0.1 A then

V = 0.1*10×10³

V = 1000 Volts

Therefore, 1000 V is the maximum voltage with which a person could come into contact while avoiding electrocution, any voltage more than 1000 V may result in fatal electrocution.

Also note that human body has very low resistance when the body is wet therefore, above calculated value would not be applicable in such case.

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inessss [21]

Answer:

600 KPa.

Explanation:

From the question given above, the following data were obtained:

Initial volume (V1) = 0.075 m³

Final volume (V2) = 0.45 m³

Final pressure (P2) = 100 KPa

Initial pressure (P1) =?

Temperature = constant

The initial pressure can be obtained by using the Boyle's law equation as shown below:

P1V1 = P2V2

P1 × 0.075 = 100 × 0.45

P1 × 0.075 = 45

Divide both side by 0.075

P1 = 45 / 0.075

P1 = 600 KPa.

Thus, the initial pressure in the balloon is 600 KPa.

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Answer:

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Explanation:

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I = Moment of Inertia

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Torque

\tau=F\times r

\tau=I\times \alpha

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Angular velocity

\omega=rev/s\times 2\pi\\\Rightarrow \omega=0.6\times 2\pi\\\Rightarrow \omega=3.76991\ rad/s

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I=\frac{1}{2}mr^2\\\Rightarrow I=\frac{1}{2}215\times 1.5^2\\\Rightarrow I=241.875\ kgm^2

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Answer:

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