With the use of electric force formula, the direction and magnitude of the net force exerted on the point charge q3 are 9.9 x
N and 66 degrees
ELECTRIC FORCE (F)
F = 
Where K = 9 x
N
/
The distance between
and
can be calculated by using Pythagoras theorem.
d = 
d = 46.7 cm = 0.467 m
For force
, substitute all the parameters into the formula above
= (9 x
x 3 x 1)/
= 2.7 x
/0.218
= 1.24 x
N
For force
, substitute all the parameters into the formula above
= (9 x
x 3 x 4)/
= 1.08 x
/0.1089
= 9.92 x
N
For force
, substitute all the parameters into the formula above
= (9 x
x 3 x 2)/
= 5.4 x
/0.1089
= 4.96 x
N
Summation of forces on Y component will be
=
-
Sin 45
= 9.92 x
- 1.24 x
Sin 45
= 9.04 x
N
Summation of forces on X component will be
=
-
Cos 45
= 4.96 x
- 1.24 x
Sin 45
= 4.08 x
N
Net Force = 
Net force = 
Net force = 9.9 x
N
The direction will be
Tan ∅ =
/
Tan ∅ = 9.04 x
/ 4.08 x 
Tan ∅ = 2.216
∅ =
(2.216)
∅ = 65.7 degrees
Therefore, the direction and magnitude of the net force exerted on the point charge q3 are 9.9 x
N and 66 degrees approximately.
Learn more about electric Force here: brainly.com/question/4053816
Comets orbit the sun just like planets do. Except a comet usually has a very elongated orbit. Thanks to the laws of gravity comets obey the same laws. A comets orbit takes it very close to the sun and then far away again.
I believe it is acceleration!
Answer:
(a) T= 38.4 N
(b) m= 26.67 kg
Explanation:
We apply Newton's second law:
∑F = m*a (Formula 1)
∑F : algebraic sum of the forces in Newton (N)
m : mass in kilograms (kg)
a : acceleration in meters over second square (m/s²)
Kinematics
d= v₀t+ (1/2)*a*t² (Formula 2)
d:displacement in meters (m)
t : time in seconds (s)
v₀: initial speed in m/s
vf: final speed in m/s
a: acceleration in m/s²
v₀=0, d=18 m , t=5 s
We apply the formula 2 to calculate the accelerations of the blocks:
d= v₀t+ (1/2)*a*t²
18= 0+ (1/2)*a*(5)²
a= (2*18) / ( 25) = 1.44 m/s²
to the right
We apply Newton's second law to the block A
∑Fx = m*ax
60-T = 15*1.44
60 - 15*1.44 = T
T = 38.4 N
We apply Newton's second law to the block B
∑Fx = m*ax
T = m*ax
38.4 = m*1.44
m= (38.4) / (1.44)
m = 26.67 kg