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liubo4ka [24]
3 years ago
9

Which statement best describes why an island's food web could be considered a closed system?

Physics
2 answers:
katovenus [111]3 years ago
8 0
I'm almost positive it is Option B but I cannot confirm. Maybe another answer can!
garik1379 [7]3 years ago
3 0
I would say Option B) because Option C) is wrong since matter cannot be created. A closed system does not exchange matter so it's not Option D). Since an island is an isolated area, Option A) is wrong.
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An object in free fall is dropped from a building. Its starting velocity is 0 m/s. Ignoring the effects of air resistance, what
Amanda [17]

Answer:

30m/s^2

Explanation:

Acceleration=Final Velocity-Initial Velocity/Time

10m/s^2= Final Velocity-0m/s/3

30m/s^2= Final Velocity

Final Velocity=30m/s^2

7 0
3 years ago
Describe the direction in which each object will accelerate. If the object won't accelerate, write "no acceleration." Explain wh
fgiga [73]

Answer:

No acceleration. All of the forces are acting equally on the paper air plane therfore It isn't going to move any where.

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3 years ago
The telescope that allowed astronomers to discover most of the planets found with the transit method was called:.
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Explanation:

4 0
2 years ago
A block is sliding down an inclined plane that makes an angle of 65o with the horizontal. If the coefficient of kinetic friction
Nezavi [6.7K]

Answer:

8.2 m/s²

Explanation:

m = mass of the block

μ = Coefficient of kinetic friction = 0.17

F_{n} = Normal force on the block by the ramp

f_{k} = kinetic frictional force

Force equation perpendicular to ramp surface is given as

F_{n} = mg Cos65

Kinetic frictional force is given as

f_{k} = \mu F_{n}

f_{k} = \mu mg Cos65

Force equation parallel to ramp surface is given as

mg Sin65 - f_{k} = ma

mg Sin65 - \mu mg Cos65 = ma

g Sin65 - \mu g Cos65 = a

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a = 8.2 m/s²

4 0
3 years ago
A motorcycle rider moving with an initial velocity of 9.2 m/s uniformly accelerates to a speed of 19.1 m/s in a distance of 32.0
777dan777 [17]

Answer:

4.38 m/s^2

Explanation:

If,

Initial velocity(u) is 9.2 m/s

Final velocity (v) is 19.1 m/s

Distance moved(s) in that period is 32 m

Therefore we use the formula,

v^2 = u^2 + 2as

; (19.1)^2 = (9.2)^2 + 2(32)a...then move the variables without a to one side..,

; 280.17 = 64a...then divide both sides by 64

; Acceleration = 4.38 m/s^2

8 0
3 years ago
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