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3 years ago

Rewrite the expression by factoring out (w-5)

Mathematics

1 answer:

lara [203]3 years ago

5 0

Answer:

(w - 5)(2w² + 7)

Step-by-step explanation:

Given

2w²(w - 5) + 7(w - 5) ← factor out (w - 5) from each term

= (w - 5)(2w² + 7)

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For every penny Sam puts into his bank, Tara puts 4 pennies into her bank. If Sam puts 10 pennies into his bank, how many pennie

devlian [24]

Answer: If Tara puts 4 pennies in for every one Sam does then after he puts in 10 she would of put 40.

She put in 40 pennies. Hope this helps ;)

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3 years ago

Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match each quadratic graph to its respectiv

ch4aika [34]

Answer:

Part 1) The function of the First graph is $f(x)=(x-3)(x+1)$

Part 2) The function of the Second graph is $f(x)=-2(x-1)(x+3)$

Part 3) The function of the Third graph is $f(x)=0.5(x-6)(x+2)$

See the attached figure

Step-by-step explanation:

we know that

The quadratic equation in factored form is equal to

$f(x)=a(x-c)(x-d)$

where

a is the leading coefficient

c and d are the roots or zeros of the function

Part 1) First graph

we know that

The solutions or zeros of the first graph are

x=-1 and x=3

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-3)(x+1)$

Find the value of the coefficient a

The vertex is equal to the point (1,-4)

substitute and solve for a

$-4=a(1-3)(1+1)$

$-4=a(-2)(2)$

$a=1$

therefore

The function is equal to

$f(x)=(x-3)(x+1)$

Part 2) Second graph

we know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to

$f(x)=a(x-1)(x+3)$

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

substitute and solve for a

$8=a(-1-1)(-1+3)$

$8=a(-2)(2)$

$a=-2$

therefore

The function is equal to

$f(x)=-2(x-1)(x+3)$

Part 3) Third graph

we know that

The solutions or zeros of the first graph are

x=-2 and x=6

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-6)(x+2)$

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

substitute and solve for a

$-8=a(2-6)(2+2)$

$-8=a(-4)(4)$

$a=0.5$

therefore

The function is equal to

$f(x)=0.5(x-6)(x+2)$

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4 years ago

Convert an annual rate of 0.224% to a generation rate (20 years)

Sedaia [141]

2.78 that will be the awnser if you go gor it

4 0

3 years ago

I need help answering this question, Asap

Natasha2012 [34]

Answer:

(-65)/17

Step-by-step explanation:

Evaluate 3/(x - 2) - sqrt(x - 3) where x = 19:

3/(x - 2) - sqrt(x - 3) = 3/(19 - 2) - sqrt(19 - 3)

19 - 3 = 16:

3/(19 - 2) - sqrt(16)

19 - 2 = 17:

3/17 - sqrt(16)

sqrt(16) = sqrt(2^4) = 2^2:

3/17 - 2^2

2^2 = 4:

3/17 - 4

Put 3/17 - 4 over the common denominator 17. 3/17 - 4 = 3/17 + (17 (-4))/17:

3/17 - (4×17)/17

17 (-4) = -68:

3/17 + (-68)/17

3/17 - 68/17 = (3 - 68)/17:

(3 - 68)/17

3 - 68 = -65:

Answer: (-65)/17

4 0

3 years ago

Read 2 more answers

Help me please! No idea

zheka24 [161]

Answer:

Step-by-step explanation:

7 0

3 years ago