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timofeeve [1]
3 years ago
9

4. True or False. Improving your muscular endurance can improve your power *

Physics
1 answer:
s344n2d4d5 [400]3 years ago
3 0

Answer:

it's true

Explanation:

A strong body allows you to perform movements and activities that require power without getting tired.

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What is the acceleration of a sinking rock if it has a mass of 0.25 kg and has a net force of 0.44 N acting on it?
charle [14.2K]

Answer: 1.76 m/s²

Explanation:

F = mass x acceleration

0.44 N = (0.25)(a)

0.44/0.25 = 1.76

a = 1.76

3 0
3 years ago
A 100 meter rope is 20 kg and is stretched with a tension of 20 newtons. If one end of the rope is vibrated with small amplitude
dezoksy [38]

Answer:

The velocity waves before rain is 10 m/s

The velocity of wave after the rope soaked up 5 kg more is 8.944 m/s

Solution:

As per the question:

Length of the rope, l = 100 m

Mass of the rope, m = 20 kg

Force due to tension in the rope, T_{r} = 20 N

Frequency of vibration in the rope, f = 10 Hz

Extra mass of the rope after being soaked in rain water, m' = 5 kg

Now,

In a rope, the wave velocity is given by:

v_{w} = \sqrt{\frac{T_{r}}{M_{d}}}         (1)

where

M_{d} = mass density

Mass density before soaking, M_{d} = \frac{m}{l} = \frac{20}{100} = 0.20

Mass density after being soaked, M_{d} = \frac{m + m'}{l} = \frac{25}{100} = 0.25

Initially, the velocity is given by using eqn (1):

v_{w} = \sqrt{\frac{20}{0.20}} = 10 m/s

The velocity after being soaked in rain:

v_{w} = \sqrt{\frac{20}{0.25}} = 8.944 m/s

3 0
3 years ago
Velocity of a car that travled 120 miles in 2 hours
Sophie [7]

60 Miles per hour 60 times 2 is 120

4 0
3 years ago
Read 2 more answers
A force of 70 N is applied to a 28 kg rock causing it to slow down from 25 m/s to 15 m/s, a change in velocity of 10 m/s. How lo
maksim [4K]

Answer: 4 s

Explanation:

Given

The applied force is 70 N

mass of the rock is 28 kg

initial velocity u=25\ m/s

final velocity v=15\ m/s

Deceleration provided by force is

a=-\dfrac{70}{28}=-2.5\ m/s^2

using the equation of motion

v=u+at\\\Rightarrow 15=25-2.5t\\\Rightarrow 2.5t=10\\\Rightarrow t=4\ s

7 0
3 years ago
An experiment is carried out to measure the extension of a rubber band for different loads.
PtichkaEL [24]

Complete question is;

An experiment is carried out to measure the extension of a rubber band for different loads.

The results are shown in the image attached.

What figure is missing from the table?

Answer:

17.3 cm

Explanation:

The image attached showed values for load, extension and initial length.

Now, the first length there is 15.2 cm and as such it's corresponding extension is 0 because it has no preceding measured length.

The second measured length is 16.2 cm. Since it's initial measured length is 15.2 cm, then the extension has a formula; final length - initial length.

This gives: 16.2 - 15.2 = 1 cm

This corresponds to what is given in the table.

For the next measured length, it is blank but we are given the extension to be 2.1 cm. Now, since the initial measured length is 15.2 cm.

Thus;

2.1 cm = Final length - 15.2 cm

Final length = 15.2 + 2.1

Final length = 17.3 cm

3 0
2 years ago
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