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posledela
3 years ago
10

When neutralizing your acid extracts, you determined how much base solution was needed to fully neutralize your acid and reach a

basic pH (pH ~ 8-9). How did you determine how much base was needed to neutralize your acid extracts
Chemistry
1 answer:
alukav5142 [94]3 years ago
6 0

Answer:

The amount of base needed is the amount that would give one mole of the hydroxide ion needed to neutralise one mole of the hydroxonium ion from the acid.

Explanation:

The chemical reaction between an acid and a base to form salt and water only is called a Neutralization reaction.  Chemically

H⁺ + OH⁻ = H₂0

Hence, one mole of hydroxonium ion (H⁺) will combine with one mole of hydroxide ion (OH⁻) to give salt and water only.

In a completely neutralized reaction, the resulting salt is formed when there is complete dissociation of the acid and base to give salt and water with a pH of 7.

In the given question, the stated pH of between 8-9 tells us that the salt produced in this particular neutralization reaction is basic or alkaline. This usually occurs when a strong base reacts with a weak acid, producing a higher concentration of the hydroxide ion at equilibrium.

Hence the amount of base needed is the amount that would give one mole of the hydroxide ion needed to neutralise one mole of the hydroxonium ion from the acid.

If the concentration or molarity of the acid is known, then the exact amount of base required to neutralize it can be calculated. This is usually done via titrating the acid against drop wise solution of the base. Neutralization usually occurs when there is a change in colour of the resulting solution. The pH of the resulting solution can be determined using a litmus paper.

A blue litmus paper is indicative of a basic solution while a red litmus paper is indicative of an acidic solution.

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A 0.98 gram sample of a volatile liquid was heated to 348 k. the gas occupied 265 ml of space at a pressure of 0.95 atm. what is
arlik [135]

Answer:

The molecular weight is Z =  111.2 \ g/mol

Explanation:

From the question we are told that

   The mass of the sample is  m =  0.98 \  g

    The temperature is  T  =  348 K

    The volume which the gas occupied is  V  =  265 \ ml  = 265 *10^{-3} L

     The pressure is  P  =  0.95 \  atm

Generally from the ideal gas equation we have that

       PV  =  n RT

Here n is the number of moles of the gas while the R is the gas constant with value  R  =  0.0821 \ atm \cdot L  \cdot mol^{-1} \cdot K^{-1}

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=>      n = \frac{ 0.95 * 265 *10^{-3} }{   0.0821 * 348}

=>      n = 0.00881 \  mol

Generally the molecular weight is mathematically represented as

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8 0
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What is reduction potential?​
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Answer:

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Explanation:

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since at this temperature, our solution contains  35g of potassium nitrate 100g  of water. The solution will be unsaturated because of the less potassium nitrate.

to make saturated solution,

mass of potassuim nitrate = 67g - 35g

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which means dissolving another  32g  of potassium nitrate in solution at 40 °C will make saturated solution.

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