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kobusy [5.1K]
3 years ago
10

The absolute value of a number is the distance it is from 0. The bug is currently to the left of 0 and the absolute value of its

location is 4. Where on the number line is it?
Mathematics
1 answer:
Ksenya-84 [330]3 years ago
6 0

Answer:

- 4

Step-by-step explanation:

The absolute value of a number renders a number positive regardless of the preceeding sign. Therefore, either a number is positive or negative, the absolute value of such number will be positive.

In a number line, 0 is the midpoint and values to the left of 0 are negative, while those to the right are positive.

For the scenario, above, the bug is to the left of 0 and has an absolute value of 4 ;

The current position of the number line will be 4 (absolute value) places to the left of 0 which is - 4 (negative numbers are in the left).

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Identify the domain of the combined function h(x) = f(x) · g(x), if the domain of f(x) is (4, 4.5], and the domain of g(x) is [4
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The area of ABED is 49 square units. Given AGequals9 units and ACequals10 ​units, what fraction of the area of ACIG is represent
stiks02 [169]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

A=b^{2}

where b is the length side of the square

we have

A=49\ units^2

substitute

49=b^{2}

b=7\ units

therefore

AB=BE=ED=AD=7\ units

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

A=(AC)(AG)

substitute the given values

A=(9)(10)=90\ units^2

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

A=(DE)(DG)

we have

DE=7\ units

DG=AG-AD=9-7=2\ units

substitute

A=(7)(2)=14\ units^2

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

A=(EF)(CF)

we have

EF=AC-AB=10-7=3\ units

CF=BE=7\ units

substitute

A=(3)(7)=21\ units^2

step 5

sum the shaded areas

14+21=35\ units^2

step 6

Divide the area of  of the shaded region by the area of ACIG

\frac{35}{90}

Simplify

Divide by 5 both numerator and denominator

\frac{7}{18}

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
I need help please! i dont know!
Kaylis [27]

Answer:

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4 0
2 years ago
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