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EleoNora [17]
3 years ago
11

in a discussion, a student makes the following statement regarding the cause of global warming, "The sun's rays penetrate the at

mosphere through the ozone hole and heat up the atmosphere and the surface, thereby causing global warming." is the student correct? why or why not? in your responce, briefly explain both phenomena.
Biology
2 answers:
Natasha2012 [34]3 years ago
6 0

sun rays will not penetrate the ozone layer. they enters the earths atmosphere by the radiation processes. Ozone Layer gets depleted by the action of chlorofluorocarbons which were released by automobiles and refrigerators. and that results in the entry of UV rays which are harmful for life forms. and global warming phenomena is a result of greenhouse effect which explains the phenomenon of the heat which entered Earth's atmosphere by radiation, does not completely reflected back! rather, it (heat) gets stored in the atmosphere which results in the increase in temperature of the earth! and global warming was useful upto some extent in our ancient days. It resulted in the melting of himalayan ice mountains which in turn resulted in the increase of sea level. but now, global warming has become a major headache for us!

bazaltina [42]3 years ago
4 0

Answer:

Student is incorrect.

Global warming is result of greenhouse effect as caused by increased level of greenhouse gases in atmosphere.

Explanation:

The student is incorrect. The solar radiations do not need ozone hole to penetrate the atmosphere. Rather, the whole layer of atmosphere is penetrable for solar radiations. Only some specific part of it such as UV rays are absorbed by ozone present in the stratosphere.

During the night, the earth's surface reflects back part of absorbed solar radiations. The greenhouse gases such as CO2, water vapor, etc. absorb the radiations reflected back by earth's surface. Since these reflected radiations do not escape to space, the earth's global temperature is increased and the process is called global warming.  

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3 years ago
Two different enzymes catalyze the same reaction and both exhibit the same Vmax. When Enzyme A was run with a 40 uM substrate, t
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Answer:

a) k_m = 4.08 uM

  V_{max} = 20.07 uM/min

b) k_m = 8.16 uM

Explanation:

Given that:

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the substrate concentration [S] = 40 uM

the initial velocity rate v = 10 uM/min

when it was 4mM, v = 20 uM/min

i.e.

at 4mM = 4000 uM;

Using Michealis -menten equation;

when v = 10

V = \dfrac{V_{max}[S]}{k_m+[S]}

∴

10 = \dfrac{V_{max}\times 40}{k_m + 40}

10 (k_m + 40) = V_{max}40

40V_{max} -10k_m = 400 --- (1)

when v= 20

20= \dfrac{V_{max}\times 4000}{k_m + 4000}

20 (k_m + 4000) = V_{max}4000

4000V_{max} -20k_m = 8000 --- (2)

equating equation (1) and (2):

40V_{max} -10k_m = 400 --- (1)

4000V_{max} -20k_m = 8000 --- (2)

let multiply equation (1) by 100 and equation (2) by 1

4000V_{max} - 1000K_m = 4000

<u>4000V_{max} - 20 k_m = 8000     </u>

  0        -980k_m = 4000

k_m = 4000/-980

k_m = 4.08 uM

replacing the value of k_m into equation (1)

40{V_max } - 10(4.08) = 400

40{V_max } - 40.8 = 400

40{V_max } = 400 +  40.8

40{V_max } = 440.8

V_{max} = 440.8/40

V_{max} = 11.02 uM/min

b)

Since V_{max} of A ie equivalent to that of B; then:

V_{max} of B = 11.02 uM/min

Here;

[S] = 80  uM

V = 10 uM/min

∴

10 = \dfrac{11.02 \times 80}{k_m + 80 }

10(k_m +80) = 881.6

10k_m = 881.6  - 800

10k_m = 81.6

k_m = 81.6/10

k_m = 8.16 uM

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