9.5⋅<span>10<span>2
</span></span>Explanation:
To figure out how many atoms of copper you get in 1 gram of copper, you need to use copper's molar mass.
Answer:Gained, Lost , Shared
Explanation:
The oxidation state tells you how many electrons an atom has GAINED.................. , LOST....................... , or SHARED........................ , in forming a compound.
Oxidation state is defined as the the total number of electrons that an atom gains or loses when forming a chemical bond with another atom.
----To form an ionic bond for example in NaCl, Na, with 11 electrons and one valence electron in its outermost shell donates or lose that valence electron to Chlorine with 17 electron and 7 in its outermost shell. Therefore Sodium, Na acquires the +1 oxidaton state to become stable and Chlorine acquires the -1 oxidation state to become stable forming the NaCl compound.
To form a covalent compound, There must be sharing of electrons between atoms.For example, in PCl3, The phosphorous atom with atomic number 15 shares its three unpaired electrons with the single valence electrons of three chlorine atoms. making the four molecules to attain stability with Phosphorous having +3 and the chlorine atoms having -1 oxidation states
The original mass of krypton 81 that is present in the ice is 6.70 grams.
<h3>How do we calculate original mass?</h3>
Original mass of any substance will be calculated as below for the decomposition reaction is:
N = N₀(1/2)ⁿ, where
N = remaining mass of krypton-81 = 1.675g
N₀ = original mass of krypton-81 = ?
n will be calculated as:
n = T/t, where
T = total time period = 458,000 years
t = half life time = 229,000 years
n = 458,000/229,000 = 2
Now putting all these values on the above equation, we get
N₀ = 1.675 / (1/2)²
N₀ = 6.70 g
Hence required mass is 6.70 g.
To know more about half life time, visit the below link:
brainly.com/question/2320811
It is a part of science because it was an invention that was made and inventions are because of science and it’s a technology because it is electrical
