Number of moles of Hydrogen gas produced = 2.5 moles
Given the balanced chemical equation,
This means, 1 mole of Mg and 2 moles of HCl gives 1 mole of Hydrogen gas.
Given that 2.5 moles of Magnesium is taken and an excess of Hydrochloric acid.
The mole ratio of Magnesium and Hydrogen = 1:1
Thus 2.5 moles of Magnesium with an excess of Hydrochloric acid will yield 2.5 moles of Hydrogen gas.
[By referring excess of HCl, we may assume that it contains at least 5 moles of HCl. Then only 2.5 moles of Mg will produce 2.5 moles of Hydrogen gas].
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Answer:
1. Sexual reproduction always requires two parents.
3. Asexual reproduction requires only one parent.
Explanation:
I don’t this answer I just want points but hope someone answers this 6
Answer:
8.4) 27.1 cm³
8.5) 0.217 mol/dm³
Explanation:
Please see attached picture for full solution.
8.4) Since the results from titrations 3-5 are within 0.10cm³ from each other, these 3 results are concordant.
8.5) Find mol of sulfuric acid to find mol of NaOH using mole ratio. Equation has already been balanced for you, so mole ratio of NaOH to H2S04 is 2:1. To find concentration of NaOH, divide the number of moles by the volume in dm³ since the units for concentration is mol/dm³, which you can think of as the number of moles of NaOH in a dm³ of solution.
1 dm³ = 1000cm³
Thus, 1cm³= 1/1000 dm³
For the basic solution:
11.2 = -log[H+]
[H+] = 6.31 x 10⁻¹²
For the acidic solution:
2.4 = -log[H+]
[H+] = 3.98 x 10⁻³
The difference:
3.98 x 10⁻³ - 6.31 x 10⁻¹²
≈ 4.0 x 10⁻³
The answer is B
