All categories

4 years ago

All of the following are physical properties of matter EXCEPT ____.

Chemistry

2 answers:

olga_2 [115]4 years ago

7 0

Mass. The mass stays the same no matter what form it is in.

timofeeve [1]4 years ago

7 0

Ability to rust is a chemical property

You might be interested in

Suppose you wanted to know how many grams of KCl would be left if 350mL of

strojnjashka [21]

Answer:

52.2g of KCl would be left

The mass of KCl will remain despite the solution is been heated

Explanation:

When you are heating a solution, just the solvent (In this case, water), will be evaporated and, in theory, the mass of KCl will remain despite the solution is been heated.

Now, the mass of KCl that you can obtain from 350mL of a 2.0M solution will be:

Moles KCl:

350mL = 0.350L * (2.0mol / L) = 0.700 moles

Mass KCl -Molar mass: 74.55g/mol-:

0.700mol * (74.55g/mol) = 52.2g of KCl would be left

8 0

3 years ago

i don't need these solved I just need the steps to solve it and. what these problems in chemistry would be called so I can look

wolverine [178]

The answers are as follows,

1. 4.71 L,

2. 3.29 L,

3. 1634.6 torr

Explanation:

All the above problems can be sorted out using the Boyle's law represents the relationship between the volume and pressure.

It can be expressed as follows,

P1V1 = P2V2

Rearranging the above expression, we get,

$$ V2 = \frac{P1V1}{V2}$

1) The first case can be solved as,

$$V 2=\frac{921 \mathrm{mm} \mathrm{Hg} \times 3.89 \mathrm{L}}{760 \mathrm{mm} \mathrm{Hg}}=4.71 \mathrm{L}$

2) The second case can be solved as,

$$V 2=\frac{25 L \times 600 \text { torr}}{4560 \text { torr}}=3.29 L$

3) The third case can be solved as,

$$P 2=\frac{7.43 L \times 1100 \text { torr}}{5 L}=1634.6 \text { torr}$

Thus the answers for all the three cases are found as,

1. 4.71 L,

2. 3.29 L,

3. 1634.6 torr respectively

6 0

3 years ago

The radioactive isotope of lead, Pb-209, decays at a rate proportional to the amount present at time t and has a half-life of 3.

Marina86 [1]

Answer:

Therefore it will take 7.66 hours for 80% of the lead decay.

Explanation:

The differential equation for decay is

$\frac{dA}{dt}= kA$

$\Rightarrow \frac{dA}{A}=kdt$

Integrating both sides

ln A= kt+c₁

$\Rightarrow A= e^{kt+c_1}$

$\Rightarrow A=Ce^{kt}$ [ $e^{c_1}=C$ ]

The initial condition is A(0)= A₀,

$\therefore A_0=Ce^{0.k}$

$\Rightarrow C=A_0$

$\therefore A=A_0e^{kt}$ .........(1)

Given that the $Pb_{209}$ has half life of 3.3 hours.

For half life $A=\frac12 A_0$ putting this in equation (1)

$\frac12A_0=A_0e^{k\times3.3}$

$\Rightarrow ln(\frac12)= 3.3k$ [taking ln both sides, $ln \ e^a=a$ ]

$\Rightarrow k=\frac{ln \frac12}{3.3}$

⇒k= - 0.21

Now A₀= 1 gram, 80%=0.8

and A= (1-0.8)A₀ = (0.2×1) gram = 0.2 gram

Now putting the value of k,A and A₀in the equation (1)

$\therefore 0.2=1e^{(-0.21)\times t}$

$\Rightarrow e^{-0.21t}=0.2$

$\Rightarrow -0.21t= ln(0. 2)$

$\Rightarrow t= \frac{ln (0.2)}{-0.21}$

⇒ t≈7.66

Therefore it will take 7.66 hours for 80% of the lead decay.

3 0

3 years ago

12.2 scientific notation

Nadya [2.5K]

This would be 1.22 x 10^1

You simply move the decimal.

If this helped you, please list me as brainliest!

3 0

3 years ago

Which particle has the most energy?

Bess [88]

Answer:

water energy yes y *jjjjjjjjjj

6 0

3 years ago

Read 2 more answers