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3 years ago

State one type of additional information that could be used to determine if these three species are closely related.

Chemistry

1 answer:

Luda [366]3 years ago

5 0

Answer:

Study the bone structure of limbs.

Explanation:

Study the bone structure of limbs can be used to find out the relatedness and relationship among three species because the pattern of bones structure is similar but the structure is different from one another due to different environmental conditions. This study provides important and useful information whether the three species are closely related or not. If they have similar bone structure than we can say that there are more chances that they are closely related to each other.

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In the reaction A+B --> C + D, what are the reactants? Answer Fast please!!!

ale4655 [162]

Answer:

C + D

Explanation:

C + D are the reactants because they are on the right side of the equation

(I hope this answer was quick enough!)

4 0

3 years ago

At sea level, water boils at 100 degrees celcius and methane boiled at -161 degrees celcius. which of these substances has a st

photoshop1234 [79]

Water because it boils quicker

8 0

3 years ago

A sample of raw mining ore contains a hydrated salt called copper sulfate tetrahydrate, CuSO4.4H2O, along with other impurities.

julsineya [31]

Answer:

88.5 % of the raw ore is CuSO4*4H2O

Explanation:

Step 1: Data given

Mass of the ore = 10.854 grams

Mass of water = 2.994 grams

Step 2: Calculate moles H2O

Moles H2O = mass H2O / molar mass H2O

Moles H2O = 2.994 grams / 18.02 g/mol

Moles H2O = 0.166 moles

Step 3: Calculate moles CuSO4*4H2O

For 1 mol CuSO4*4H2O we have 4 moles H2O

For 0.166 moles H2O we have 0.166/4 = 0.0415 moles CuSO4*4H2O

Step 4: Calculate mass CuSO4*4H2O

Mass CuSO4*4H2O = moles * molar mass

Mass CusO4*4H2O = 0.0415 moles * 231.67 g/mol

Mass CuSO4*4H2O = 9.61 grams

Step 5: Calculate mass % of CuSO4*4H2O

Mass % = (9.61 grams / 10.854 grams )*100 %

Mass % = 88.5 %

88.5 % of the raw ore is CuSO4*4H2O

4 0

4 years ago

Consider the combustion reaction for octane (C8H18), which is a primary component of gasoline.

lesya692 [45]

Answer:

$n_{CO_2}=1.93 gCO_2$

Explanation:

Hello,

In this case, considering the given chemical reaction, we can use the molar mass of octane (114.23 g/mol) and the 2:16 molar ratio with carbon dioxide to compute the emitted moles of CO2 to the atmosphere via the following stoichiometric procedure:

$n_{CO2}=27.6gC_8H_{18}*\frac{1molC_8H_{18}}{114.23gC_8H_{18}} *\frac{16molCO_2}{2molC_8H_{18}} \\\\n_{CO_2}=1.93 gCO_2$

Which also corresponds to the following mass:

$m_{CO_2}=1.93molCO_2*\frac{44gCO_2}{1molCO_2} \\\\m_{CO_2}=85.0gCO_2$

Best regards.

6 0

3 years ago

Which of the following is an acid-base indicator? A) hydrochloric acid B)sodium hydroxide C)water D)phenolphthalein

KATRIN_1 [288]

D the answer is phenolphthalein

4 0

4 years ago

Read 2 more answers