(9x^2+10x+c) = (3x+b)^2
= 9x^2 + 6b x+ b^2
1) 6b= 10
b+ 5/3
2) c=b^2
c= (5/3) ^2
c= 25/9
(9x^2+10x+25/9)=(3x+5/3)^2
I hope this helps:)
Answer:
4 x 10^-2
Step-by-step explanation:
So the number is written in two parts:
Just the digits (with the decimal point placed after the first digit), followed by
× 10 to a power that puts the decimal point where it should be. In this case you would move the decimal two places back by multiplying it to the negative second power. I hope that helps! :D
The answer is square root of 8
The remainder is five. heres the proof.
Answer:
si por que esta bien hecha
