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Kruka [31]
3 years ago
10

Classify the following compounds as ionic or covalent: a. MgCl2 b. Na2S c. H2O d. H2S

Chemistry
2 answers:
tia_tia [17]3 years ago
6 0

Explanation:

A compound in which there occurs sharing of electrons from atom to another is known as a covalent compound.

For example, atomic number of hydrogen is 1 and atomic number of oxygen is 8.

As electronic distribution of oxygen atom is 2, 6. So, in order to complete its octet it will share its valence electrons with two hydrogen atoms.

Hence, it will form H_{2}O compound which is covalent in nature.

Whereas, a compound in which there occurs transfer of electrons from one atom to another is known as an ionic compound.

For example, atomic number of magnesium is 12 and atomic number of chlorine is 17. So, in order to attain stability Mg donates its valence electrons to chlorine atoms which will form an ionic compound MgCl_{2}.

Thus, we can conclude that out of the given options compounds are classified as follows.

  • Ionic compound - MgCl_{2} and Na_{2}S
  • Covalent compound - H_{2}O and H_{2}S
k0ka [10]3 years ago
4 0
MgCl2 is ionic because it is a positive metal bonding with a negative nonmetal. Na2S is ionic for the same reason. H2O and H2S are both covalent because they are two nonmetals bonded together.
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The solubility of BaCO3(s) in water at a certain temperature is 4.4 10–5 mol/L. Calculate the value of Ksp for BaCO3(s) at this
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Answer : The value of K_{sp} for BaCO_3 is 19.36\times 10^{-10}mole^2/L^2.

Solution : Given,

Solubility of BaCO_3 in water = 4.4\times 10^{-5}mole/L

The barium carbonate is insoluble in water, that means when we are adding water then the result is the formation of an equilibrium reaction between the dissolved ions and undissolved solid.

The equilibrium equation is,

                            BaCO_3\rightleftharpoons Ba^{2+}+CO^{2-}_3

Initially                   -                   0        0

At equilibrium       -                   s         s

The Solubility product will be equal to,

K_{sp}=[Ba^{2+}][CO^{2-}_3]

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K_{sp}=(4.4\times 10^{-5}mole/L)^2=19.36\times 10^{-10}mole^2/L^2

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3 years ago
In the following net ionic equation, identify each reactant as either a Bronsted-Lowry acid or a Bronsted-Lowry base. HCN(aq) H2
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Answer:

Explanation:

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Bronsted-Lowry defined acid as a molecule or ion which donates a proton while a base is a molecule or ions that accepts the proton. This definition can be extended to include acid -base titrations in non-aqueous solutions.

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From the given information:

\mathsf{HCN _{(aq)} + H_2O_{(l)} \to CN^{-}_{(aq)} + H_3O_{(aq)}}

From above:

We will see that HCN releases an H⁺ ion, thus it is a Bronsted-Lowry acid

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The formula of the reactant that acts as a proton donor is <u>HCN</u>

The formula of the reactant that acts as a proton acceptor is <u>H2O</u>

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