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Olin [163]
3 years ago
14

The number of atoms in 5.78 mol NH4NO3. Show your work.

Chemistry
2 answers:
IRINA_888 [86]3 years ago
6 0

Answer:

3.481 x 10²⁴ atoms

Explanation:

Data Given:

Number of moles of NH₄NO₃ = 5.78 mol

Number of atoms of NH₄NO₃ = ?

Solution:

Formula used

                  no. of moles = no. of atoms / Avogadro's number

As we have to find no. of atoms

So, we have to rearrange the above equation

                  no. of atoms = no. of moles x Avogadro's number . . . . . (1)

Where

Avogadro's number = 6.022 x 10²³ atoms

Put values in above Equation 1

                      no. of atoms = 5.78 mol x 6.022 x 10²³ atoms/mol

                      no. of atoms = 3.481 x 10²⁴ mol

So,

no. of atoms in 5.78 mole NH₄NO₃ = 3.481 x 10²⁴ atoms

umka21 [38]3 years ago
6 0

Answer:

The answer is 3.48 × 10²⁴

Explanation:

Avogadro's constant/number is used to get the actual number of particles (atoms or ions) in a molecule of a substance.

Avogadro's number is 6.022 × 10²³

To get the actual number of atoms in a substance: avogadro's constant is multiplied by the number of moles of the substance

Hence,

number of atoms = 5.78 × 6.022 × 10²³

number of atoms in 5.78 moles of NH₄NO₃ = 3.48 × 10²⁴

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Answer:

      CH_2O_2

Explanation:

The question in English is:

<em>5. From 100 g of a compound formed by carbon, hydrogen and oxygen, 39.132 g of water and 95.656 g of CO₂ are obtained. Determine:</em>

<em />

<em>A. The empirical formula of the compound.</em>

<h2>Solution</h2>

All the carbon of the compound ends as carbon in the CO₂ and all the hydrogen in the compound ends in the water.

<u>1. C in CO₂</u>

Divide the mass of CO₂ by its molar mass and multiply by the molar mass of C:

        96.656g\times \dfrac{12.011g/mol}{44.01g/mol}=26.379gC

<u>2. H in H₂O</u>

Divide the mass of H₂O by its molar mass and multiply by 2 times the molar mass of H:

        39.132g\times \dfrac{(2\times 1.008)g/mol}{18.015g/mol}=4.379gH

<u>3. Calculate O by difference</u>

     100g-26.379g-4.379g=69.242gO

<u>4.Divide the mass of each element by the corresponding atomic mass to find the number of moles of the element</u>

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  • H: 4.379g / (1.008g/mol) = 4.344 mol
  • O: 69.242g / (15.999g/mol) = 4.328 mol

<u />

<u>5. Divide by the least number of moles</u>

  • C: 2.196/2.196 = 1
  • H: 4.344 / 2.196 ≈ 2
  • O: 4.328 / 2.196 ≈ 2

Those are the subscripts of the empirical formula:

<u>6. Empirical formula</u>

         CH_2O_2

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