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Anastaziya [24]
3 years ago
8

Ethyne or acetylene can be hydrogenated to change from the triple bonded C2H2 to the double-bonded C2H4. Adding hydrogens in org

anic chemistry is called reduction. Adding and removing hydrogens are important steps in chemical manufacturing. Calculate the value of ΔS° for the catalytic hydrogenation of acetylene to ethene,
C2H2 (g) + H2 (g) --> C2H4 (g)


A. +18.6 J/mol K

B. -18.6 J/mol K

C. -112.0 J/mol K

D. +112.0 J/mol K

Chemistry
1 answer:
GaryK [48]3 years ago
6 0

The correct answer is

C. -112.0 J/mol K

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Answer: The balanced reaction is:
<span>2 C6H14(g)+ 19 O2(g) → 12 <span>CO2</span>(g)+ 14 H2O(g)

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At sea level, a kilogram weighs approximately:
Marysya12 [62]
The answer would be b, or 2
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In the reaction fecl2 + 2naoh fe(oh)2(s) + 2nacl, if 6 moles of fecl2 are added to 6 moles of naoh, how many moles of fecl2 woul
pychu [463]
The balanced chemical reaction would be 

<span>fecl2 + 2naoh =  fe(oh)2(s) + 2nacl

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Please help with #2 and #3
Vaselesa [24]

Answer:

2. V_2=17L

3. V=82.9L

Explanation:

Hello there!

2. In this case, we can evidence the problem by which volume and temperature are involved, so the Charles' law is applied to:

\frac{V_2}{T_2}=\frac{V_1}{T_1}

Thus, considering the temperatures in kelvins and solving for the final volume, V2, we obtain:

V_2=\frac{V_1T_2}{T_1}

Therefore, we plug in the given data to obtain:

V_2=\frac{18.2L(22+273)K}{(45+273)K} \\\\V_2=17L

3. In this case, it is possible to realize that the 3.7 moles of neon gas are at 273 K and 1 atm according to the STP conditions; in such a way, considering the ideal gas law (PV=nRT), we can solve for the volume as shown below:

V=\frac{nRT}{P}

Therefore, we plug in the data to obtain:

V=\frac{3.7mol*0.08206\frac{atm*L}{mol*K}*273.15K}{1atm}\\\\V=82.9L

Best regards!

6 0
3 years ago
ILL MARK BRAINIEST WHOEVER ANSWERS CORRECTLY
natulia [17]

Answer:

I think its A

sorry if im wrong

Explanation:

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