The problem states that the distance travelled (d) is
directly proportional to the square of time (t^2), therefore we can write this in
the form of:
d = k t^2
where k is the constant of proportionality in furlongs /
s^2
<span>Using the 1st condition where d = 2 furlongs, t
= 2 s, we calculate for the value of k:</span>
2 = k (2)^2
k = 2 / 4
k = 0.5 furlongs / s^2
The equation becomes:
d = 0.5 t^2
Now solving for d when t = 4:
d = 0.5 (4)^2
d = 0.5 * 16
<span>d = 8 furlongs</span>
<span>
</span>
<span>It traveled 8 furlongs for the first 4.0 seconds.</span>
Explanation:
d= 80km = 8000m
t = 45 min = 45/60 h
= 0.75 h
V= ?
we know that,
V = d /t
or,V= 80 km / 0.75 h
- or, V= 106.67 km/hr
or,V= 106.67×1000m / 3600 s
2. or, V= 29.63 m/s
Answer: 2.1 × 10^7 m/s
Explanation:
Please see the attachments below
It depends on Mass and velocity
Answer:
a) Δx = 180.59 m
b) T = 6001 N
Explanation:
a)
According to Newton's second law, which says that acceleration is directly proportional to the net force, the equation is equal to:
ΣF = m*a = T-f
Clearing a, and solving:
a = (T-f)/m = (T-f)/2*m = (12000-5800)/(2*700) = 4.43 m/s^2
To evaluate the final speed the following equation will be used:
vf^2 = vi^2 + 2*a*Δx = 0 + 2*a*Δx = 2*a*Δx
Clearing Δx:
Δx = vf^2/2*a = (40 m/s)^2/(2* 4.43 m/s^2) = 180.59 m
b)
The tension is equal to:
T = m*a + f = (700 kg * 4.43 m/s^2) + 2900 N = 6001 N
