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tatuchka [14]
3 years ago
5

What is 1/3 multiply 2/4

Mathematics
2 answers:
Greeley [361]3 years ago
4 0

Answer:

1/3 * 2/4 = 1/3 * 1/2 = (1*1)/(3*2) = 1/6

siniylev [52]3 years ago
4 0

Answer:

1/3 * 2/4 = 1 /6

≅ 0.1666667

Step-by-step explanation:

1 /3  * 2/ 4  = <u>1·2_=2/</u>12  = <u>__1/6 · 2/2  = 1/6</u>

Hope this helped!!!

                               

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bonufazy [111]

Answer:

Q1: 11x - 8

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3 years ago
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The function in Exercise represents the rate of flow of money in dollars per year. Assume a 10-year period at 8% compounded cont
anzhelika [568]

Answer:

a) The present value is 688.64 $

b) The accumulated amount is 1532.60 $

Step-by-step explanation:

<u>a)</u><u> The preset value equation is given by this formula:</u>

P=\int^{T}_{0}f(t)e^{-rt}dt

where:

  • T is the period in years (T = 10 years)
  • r is the annual interest rate (r=0.08)

So we have:

P=\int^{T}_{0}(0.01t+100)e^{-rt}dt

Now we just need to solve this integral.

P=\int^{T}_{0}0.01te^{-rt}dt+\int^{T}_{0}100e^{-rt}dt

P=e^{-0.08t}(-1.56-0.13t)|^{10}_{0}+1250e^{-0.08t}|^{10}_{0}

P=0.30+688.34=688.64 $

The present value is 688.64 $

<u>b)</u><u> The accumulated amount of money flow formula is:</u>

A=e^{r\tau}\int^{T}_{0}f(t)e^{-rt}dt

We have the same equation but whit a term that depends of τ, in our case it is 10.

So we have:

A=e^{r\tau}\int^{T}_{0}(0.01t+100)e^{-rt}dt=e^{0.08\cdot 10}P

A=e^{0.08\cdot 10}688.64=1532.60 $

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Have a nice day!

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Hey there! :)

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Percentage: 36/100 × 100 = 36%.

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