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3 years ago

Are ADEF and ARPQ congruent?

Mathematics

1 answer:

kari74 [83]3 years ago

8 0

Answer:

B. Yes. ΔDEF can be mapped to ΔRPQ by a 180° rotation about the origin followed by a translation 2 units down.

Step-by-step explanation:

^^^just did it on edg and got it right.

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A number from 1 to 100, inclusive, is selected at random. What is the probability that the

Gala2k [10]

Answer:i might be wrong but i believe its b

Step-by-step explanation:

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3 years ago

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What’s the probability?

son4ous [18]

Answer:

$\frac{1}{8}$

Step-by-step explanation:

The probability for a flip on either side of the coin is always 50% or $\frac{1}{2}$

So to get the probability for the three flips just do:

$(\frac{1}{2}) ^{3}$ or $\frac{1}{2}$ × $\frac{1}{2}$ × $\frac{1}{2}$

Either way you solve it the answer is $\frac{1}{8}$

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3 years ago

Please help!!As soon as possible!!

pychu [463]

Answer: Their equations have different y-intercept but the same slope

Step-by-step explanation:

Since, the slope of the line passes through the points (2002,p) and (2011,q) is,

$m_1 = \frac{q-p}{2011-2002} = \frac{q-p}{9}$

Similarly, the slope of the line asses through the points (2,p) and (11,q) is,

$m_2 = \frac{q-p}{11-2} = \frac{q-p}{9}$

Since, $m_1 = m_2$

Hence, both line have the same slope.

Now, the equation of the line one having slope $m_1$ and passes through the point (2002,p) is,

$y - p = \frac{q-p}{9}(x-2002)$

Put x = 0 in the above equation,

We get, $y = \frac{2000(p-q)}{9}+p$

The y-intercept of the line one is $(0, \frac{2000(p-q)}{9}+p)$

Also, the equation of second line having slope $m_2$ and passes through the point (2,p)

$y-p=\frac{q-p}{9}(x-2)$

Put x = 0 in the above equation,

We get, $y = \frac{2(p-q)}{9}+p$

The y-intercept of the line one is $(0, \frac{2(p-q)}{9}+p)$

Thus, both line have the different y-intercepts.

⇒ Third option is correct.

6 0

3 years ago

The triangles are similar

hoa [83]

Answer:

Part 1) $x=16\ units$

Part 2) $x=23\ units$

Part 3) $AE=20\ units$

Part 4) $x= 6.25\ units$

Part 5) $x=26.67\ in$

Step-by-step explanation:

Part 1) we know that

If two triangles are similar

then

the ratio of their corresponding sides are equal

In this problem

$\frac{12}{3}=\frac{x}{4}\\\\3x=12*4\\ \\x=48/3\\ \\x=16\ units$

Part 2) we know that

If two triangles are similar

then

the ratio of their corresponding sides are equal

In this problem

$\frac{36}{12}=\frac{39}{(x-10)}\\\\3(x-10)=39\\ \\x=(39/3)+10\\ \\x=23\ units$

Part 3) we know that

If two triangles are similar

then

the ratio of their corresponding sides are equal

In this problem

$\frac{AB}{CD}=\frac{AE}{ED}$

substitute the values

$\frac{10}{4}=\frac{2x+10}{x+3}$

$2.5(x+3)=2x+10$

$2.5x+7.5=2x+10$

$2.5x-2x=10-7.5$

$0.5x=2.5$

$x=5\ units$

$AE=2x+10=2*5+10=20\ units$

Part 4) we know that

If two triangles are similar

then

the ratio of their corresponding sides are equal

In this problem

$\frac{4}{5}=\frac{5}{x}\\ \\4x=5*5\\ \\ x=25/4\\ \\ x= 6.25\ units$

Part 5) we know that

If two triangles are similar

then

the ratio of their corresponding sides are equal

In this problem

$\frac{30}{x}=\frac{45}{40}\\ \\45x=30*40\\ \\x=1,200/45\\ \\ x=26.67\ in$

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3 years ago

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How was y'all day. I hope it is good

Readme [11.4K]

Answer:

My day has been going great! And I hope your day is going great too! :)

Step-by-step explanation: You are a perfect human :>

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3 years ago