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4 years ago

Are ADEF and ARPQ congruent?

Mathematics

1 answer:

kari74 [83]4 years ago

8 0

Answer:

B. Yes. ΔDEF can be mapped to ΔRPQ by a 180° rotation about the origin followed by a translation 2 units down.

Step-by-step explanation:

^^^just did it on edg and got it right.

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Mr. Ellis deposited $3,700 into a savings account for which interest is compounded quarterly at a rate of 1.84% how much interes

Bad White [126]

A=p (1+I/k^kn

A future value ?
P principle 3700
i interest rate 0.0184
K compounded quarterly 4
N time 6 years

A=3,700×(1+0.0184÷4)^(4×6)
A=4,130.84

Interest earned=A-p
4,130.84−3,700=430.84

Hope it helps:-)

7 0

3 years ago

Read 2 more answers

Send help! trigonometry questions...see photo

alukav5142 [94]

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6 0

4 years ago

Henry and Saul live 14 miles apart. Saul and Claire live 20 miles apart

8_murik_8 [283]

So Henry and Saul live 14 miles apart and Clair and Saul live 20 miles apart, that it's really, unless there is more to go off of here

6 0

3 years ago

PLEASEEE ITS EASY ALGEBRA 1 ):

Naya [18.7K]

Answer:

6, 7, and 8

Step-by-step explanation:

2x/3 + 7 > 11

Subtract 7 from both sides

2x/3 > 4

Multiply both sides by 3

2x > 12

Divide both sides by 2

x > 6

6, 7, and 8 are the ones that work

5 0

3 years ago

The table below shows the distance a train traveled over time. How can you determine the equation that represents this relations

n200080 [17]

Answer:

see the explanation

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $k=\frac{y}{x}$ or $y=kx$

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

Let

x ----> the time in seconds

y ---> the distance in meters

In this problem we have a proportional relationship between the variables x and y

Find the constant of proportionality k

$k=\frac{y}{x}$

For x=2, y=25 ---> $k=\frac{25}{2}=12.5$

For x=4, y=50 ---> $k=\frac{50}{4}=12.5$

For x=6, y=75 ---> $k=\frac{75}{6}=12.5$

For x=8, y=100 ---> $k=\frac{100}{8}=12.5$

The value of k is $12.5\ \frac{m}{sec}$

In this problem the value of k or slope represent the speed of the train

The linear equation is equal to

$y=12.5x$

$Distance=12.5Time$

4 0

4 years ago