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V125BC [204]
3 years ago
8

Are ADEF and ARPQ congruent?

Mathematics
1 answer:
kari74 [83]3 years ago
8 0

Answer:

B.  Yes. ΔDEF can be mapped to ΔRPQ by a 180° rotation about the origin followed by a translation 2 units down.

Step-by-step explanation:

^^^just did it on edg and got it right.

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I need help with question 3
agasfer [191]

Answer:

see explanation

Step-by-step explanation:

To find the y-intercept let x = 0, in the equation

6x - 3y = 15 → (1)

x = 0 : - 3y = 15 ⇒ y = - 5 ⇒ (0, - 5) ← y- intercept

x + 3y = - 8 → (2)

x = 0 : 3y = - 8 ⇒ y = -\frac{8}{3} ⇒ (0, - \frac{8}{3}) ← y- intercept


4 0
3 years ago
Simplify completely*******​
Elodia [21]

Answer:

\displaystyle \frac{x - 12}{4}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Terms/Coefficients
  • Factoring

Step-by-step explanation:

<u>Step 1: Define</u>

\displaystyle \frac{2x - 24}{8}

<u>Step 2: Simplify</u>

  1. [Fraction - Numerator] Factor:                                                                       \displaystyle \frac{2(x - 12)}{8}
  2. [Fraction] Reduce:                                                                                         \displaystyle \frac{x - 12}{4}
8 0
2 years ago
Read 2 more answers
Please answer the question in the photo, thanks!
belka [17]

Answer:

\therefore 2\dfrac{1}{3}  \div \left ( -3\dfrac{2}{3} \right ) = -\dfrac{7}{11}

Step-by-step explanation:

The question relates to dividing a fraction by proper and another fraction

The given expression is presented as follows;

2\dfrac{1}{3}  \div \left ( -3\dfrac{2}{3} \right )

We rearrange the fractions as improper  fractions for easier division as follows;

2\dfrac{1}{3}  = \dfrac{7}{3}

-3\dfrac{2}{3} = -\dfrac{11}{3}

Therefore, we have;

2\dfrac{1}{3}  \div \left ( -3\dfrac{2}{3} \right ) = \dfrac{7}{3} \div \left (-\dfrac{11}{3} \right ) = \dfrac{7}{3} \times \left (\dfrac{1}{-\dfrac{11}{3} } \right ) = \dfrac{7}{3} \div \left (-\dfrac{3}{11} \right ) =-\dfrac{7}{11}

\therefore 2\dfrac{1}{3}  \div \left ( -3\dfrac{2}{3} \right ) = -\dfrac{7}{11}

4 0
2 years ago
Substitute for x+2y=12 and x=y-12<br><br> PLEASE HELP !
yan [13]

Answer:

x = -4, y = 8

Step-by-step explanation:

y - 12 + 2y = 12

=> 3y = 24

=> y = 8

x = 8 - 12

=> x = -4

7 0
3 years ago
Read 2 more answers
suppose you win a contest at the start of 9th grade that deposited $3000 in an account that pays 5% annual interest compound con
tiny-mole [99]
A=pe^rt
A=3,000×e^(0.05×8)
A=4,475.47
5 0
3 years ago
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