A 0.060 kg ball hits the ground with a speed of –32 m/s. The ball is in contact with the ground for 45 milliseconds and the grou
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<h2><u>Required</u><u> </u><u>Answer</u><u>:</u></h2>
The body will <u>stay at rest </u>(Option D). It is because a force of magnitude 50 N is pulled towards left and another force is pulling it towards right with same magnitude 50 N. So, the direction of force is opposite and magnitude is same i.e. 50 N. So, they will cancel each other and net force is 0. Hence, there would be no acceleration.
- Option A - Showing acceleration
- Option B - Showing acceleration
- Option C - Change of direction due to Net force
Hence, these options are incorrect because they are only possible when net external force is non-zero. Staying at rest i.e. Option D means there is no motion and hence no acceleration, this shows that net force is 0
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Answer:
D = 18000 kg/m3
V = 2.5*10{-7}m3
Explanation:
From the Archimedes principle,
Weight of fluid displaced = W_{air} - W_{water}
W_{air} = 4.5 gm
W_{water} = 4.25 gm
W = 2.4525*10{-3} N
D = 18000 kg/m3
b) object Volume can be obtained as ,
V = 2.5*10{-7}m3