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gavmur [86]
2 years ago
12

A 0.060 kg ball hits the ground with a speed of –32 m/s. The ball is in contact with the ground for 45 milliseconds and the grou

nd exerts a +55 N force on the ball.
What is the magnitude of the velocity after it hits the ground?
Physics
1 answer:
SCORPION-xisa [38]2 years ago
3 0

Answer:

imma try and get it wrong

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Find the potential energy of a 2 kg ball 15 m in the air.
mart [117]

Answer:

294.3 Joules

Explanation:

2kg*9.81m/s^2*Δ15=294.3J

8 0
3 years ago
All of the following are physical properties of hydrogen peroxide except it
tankabanditka [31]
The answer to this question is B, Reacts with sunlight.

The 2 main properties of substances are their physical properties and chemical properties. 
Physical properties are some observable/measurable characteristics, such as their color, mass, state, melting point, conductivity etc.

Meanwhile, for chemical properties, they're about how the substance reacts with other substances, such as metals react with acid to form hydrogen. And by the word "react", it means there's no way turn the reaction product back to the original substance without using chemical methods such as heating or electrolysis. 

Therefore, all the choices above are physical properties of hydrogen peroxide except for B, as it is the only choice that relates to the substance reacting to another substance. 
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3 years ago
Where were the girls heading when the car broke down?<br> in the movie *hidden figures*
Ilia_Sergeevich [38]

Explanation:

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5 0
3 years ago
Dust settling out of the air<br> chemical change or physical change
mars1129 [50]
Physical changes: melting, evaporating, and condensation. This is a physical change.
7 0
2 years ago
Read 2 more answers
How much momentum will a dumb-bell of mass 10 kg transfer
frosja888 [35]

We want to find how much momentum the dumbbell has at the moment it strikes the floor. Let's use this kinematics equation:

Vf² = Vi² + 2ad

Vf is the final velocity of the dumbbell, Vi is its initial velocity, a is its acceleration, and d is the height of its fall.

Given values:

Vi = 0m/s (dumbbell starts falling from rest)

a = 10m/s² (we'll treat downward motion as positive, this doesn't affect the result as long as we keep this in mind)

d = 80×10⁻²m

Plug in the values and solve for Vf:

Vf² = 2(10)(80×10⁻²)

Vf = ±4m/s

Reject the negative root.

Vf = 4m/s

The momentum of the dumbbell is given by:

p = mv

p is its momentum, m is its mass, and v is its velocity.

Given values:

m = 10kg

v = 4m/s (from previous calculation)

Plug in the values and solve for p:

p = 10(4)

p = 40kg×m/s

6 0
3 years ago
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