Refer to the diagram shown below.
Let I = the moment of inertia of the wheel.
α = 0.81 rad/s², the angular acceleration
r = 0.33 m, the radius of the weel
F = 260 N, the applied tangential force
The applied torque is
T = F*r
= (260 N)*(0.33 m)
= 85.8 N-m
By definition,
T = I*α
Therefore,
I = T/α
= (85.8 N-m)/(0.81 rad/s²)
= 105.93 kg-m²
Answer: 105.93 kg-m²
Answer:
Explanation:
a ) work done by gravitational force
= mg sinθ ( d + .21)
Potential energy stored in compressed spring
= 1/2 k x²
= .5 x 431 x ( .21 )²
= 9.5
According to conservation of energy
mg sinθ ( d + .21) = 9.5
3.2 x 9.8 x sin 30( d + .21 ) = 9.5
d = 40 cm
b )
As long as mg sin30 is greater than kx ( restoring force ) , there will be acceleration in the block.
mg sin30 = kx
3.2 x 9.8 x .5 = 431 x
x = 3.63 cm
When there is compression of 3.63 cm in the spring , block will have maximum velocity. there after its speed will start decreasing.
You can use the equation V=Vo+at since the acceleration is constant. Plugging in the values you know, you will get an answer of 3.75 seconds
Answer:
The change in potential energy is 
Explanation:
From the question we are told that
The magnitude of the uniform electric field is 
The distance traveled by the electron is 
Generally the force on this electron is mathematically represented as
Where F is the force and q is the charge on the electron which is a constant value of 
Thus
Generally the work energy theorem can be mathematically represented as
Where W is the workdone on the electron by the Electric field and 
is the change in kinetic energy
Also workdone on the electron can also be represented as
Where 
considering that the movement of the electron is along the x-axis
So
substituting values
Now From the law of energy conservation
Where 
is the change in potential energy
Thus
10 is the number that is subtracted from it is the MINUEND
4 is the number being subtracted its then the SUBTRAHEND
6 is the result it is then the DIFFERENCE
so the correct term for 4 is SUBTRAHEND
