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Nesterboy [21]
4 years ago
5

When the moon is waxing, it's lighted part appears

Physics
2 answers:
kvv77 [185]4 years ago
7 0
To increase it's size

Waxing is the opposite of waning, which is to decrease.
anygoal [31]4 years ago
5 0
When the moon is waxing, the portion of the
lighted part that we see is growing each night.
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Nataly_w [17]
Are you good is every thing alr
5 0
3 years ago
A helicopter’s velocity increases from 35 m/s to 70 m/s in 10 seconds. What is the acceleration of this helicopter?
Alenkinab [10]
3.5 meters per second second is the acceleration because we know that acceleration is change in velocity over time and the change is velocity here is 35 and the time is 10 so we can simply divide 35 by 10 which is 3.5 m/s squared
3 0
3 years ago
The average Intensity of the electromagnetic field due to sunlight at the surface of the earth is 1400 W/m^2. Calculate the maxi
Ann [662]

Answer:

1027 N/C

3.42 x 10⁻⁶ T

Explanation:

I = Intensity of electromagnetic field = 1400 W/m²

E₀ = Maximum value of electric field

Intensity of electromagnetic field is given as

I = (0.5) ε₀ E₀² c

1400 =  (0.5) (8.85 x 10⁻¹²) (3 x 10⁸) E₀²

E₀ = 1027 N/C

B₀ = maximum value of magnetic field

using the equation

E₀ = B₀ c

1027 = B₀ (3 x 10⁸)

B₀ = 3.42 x 10⁻⁶ T

4 0
3 years ago
A 24-V battery is powering a light bulb with a resistance of 3.0 ohms. What is the current flowing through the bulb? A) 7.20 A B
Usimov [2.4K]

According to Ohm's law for a portion of the circuit we have:

U=RI=>I=U/R=24/3=8 A

The correct answer is  B


3 0
3 years ago
A tin can has a radius of 0.0410m and is 185 m high if the air is removed from inside the can how much forces will the outside a
grin007 [14]

The force exerted on the bottle is 532 N

Explanation:

When the air is removed from inside the bottle, vacuum is created, therefore the external pressure (the atmospheric pressure) is no longer balanced, and it creates a net force downward on the can.

The pressure is related to the force by the equation:

p=\frac{F}{A}

where

p is the pressure

F is the force

A is the area of the can

Here we have:

p=1.01\cdot 10^5 Pa is the atmospheric pressure

r = 0.0410 m is the radius of the can, so the area is

A=\pi r^2 = \pi (0.0410)^2=5.27\cdot 10^{-3}m^2

And solving for F, we can find the force on the can:

F=pA=(1.01\cdot 10^5)(5.27\cdot 10^{-3})=532 N

Learn more about pressure:

brainly.com/question/4868239

brainly.com/question/2438000

#LearnwithBrainly

3 0
4 years ago
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