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SashulF [63]
3 years ago
6

A dilute aqueous solution of an organic compound soluble in water is formed by dissolving 2.35 g of the compound in water to for

m 0.250 L of solution. The resulting solution has an osmotic pressure of 0.605 atm at25∘CAssuming that the organic compound is a nonelectrolyte, what is its molar mass?
Chemistry
1 answer:
Sliva [168]3 years ago
5 0

Answer:

  • The molar mass is 380. g/mol (three significant figures)

Explanation:

1) <em>Osmotic pressure</em> is a colligative property, which means that it depends on the number of particles of solute present in the solvent.

2) The mathematical expression that relates osmotic pressure with the <em>concentration of solute</em> is:

  • Π = i M R T

Where:

  • Π is the osmotic pressure,
  • i is the van't Hoff factor,
  • M is the molarity concentration of the solute,
  • R is the universal constant,
  • T is the temperature in kelvins.

3) Here:

  • i = 1, because the solute is a summed to be a nonelectrolyte,
  • T = 25 + 273.15 K = 293.15,
  • R = 0.08206 L atm mol⁻¹ K⁻¹,
  • Π = 0.605 atm

4) <u>Calculate M</u>

  • M = Π / ( i R T) =

             = 0.605 atm / (1 × 0.08206 L atm mol⁻¹ K⁻¹ × 298.15 K) =

             = 0.0247 atm (three significant figures)

5) <u>Calculate number of moles, from molarity definition</u>:

  • M = n / V (liters)

            ⇒ n = M × V (in liters) = 0.0247 M × 0.250 liter =

                    = 0.00618 moles

6) <u>Calculate molar mass</u>:

  • Molar mass = mass in grams / number of moles =

                             = 2.35 g / 0.00618 moles

                             = 380 g/mol ← answer

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