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Cloud [144]
3 years ago
5

Read the article and answer the 6 questions in it.

Chemistry
2 answers:
Sliva [168]3 years ago
7 0

Answer:

Yea.....where is the article and the 6 questions?

boyakko [2]3 years ago
7 0

Answer:

Answering

Explanation:

do u want us to tell u what we got?

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5 ohms of resistance

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Read the following chemical equation.
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QUESTION 10
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The molar heat of fusion of gold is 12.550 kJ mol–1. At its melting point, how much mass of melted gold must solidify to release
KATRIN_1 [288]

The mass of melted gold to release the energy would be  3, 688. 8 Kg

<h3>How to determine the mass</h3>

The formula for quantity of energy is given thus;

Q = n × HF

Where n represents number of moles

HF  represents  heat of fusion

To find the number of moles, we have

235.0 = n × 12.550

number of moles = \frac{235}{12. 550} = 18. 725 moles

Note that molar mass of Gold is 197g/ mol

Let's note that;

Number of moles = mass/ molar mass

Mass = number of moles × molar mass

Mass = 18. 725 × 197

Mass = 3, 688. 8 Kg

Thus, the mass of melted gold to release the energy would be  3, 688. 8 Kg

Learn more about molar heat of fusion here:

brainly.com/question/15634085

#SPJ1

8 0
1 year ago
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