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1 year ago

The 7.4 N weight is in equilibrium under

Physics

1 answer:

zhenek [66]1 year ago

7 0

a) Magnitude of force is 5.37N

b) Angle of force is - 37.88°

<h3>What is force?</h3>

In physics, we define a force is an influence that can change the motion of object. A force can cause an object with mass to change to accelerate.

Given force from above is 5.9N

∑Fₓ = F₁ₓ + F₂ₓ+F₃ₓ = 0

F₂ cos 44° + Fₓ = 0

Fₓ = - 5.9 cos44°

= - 4.24 N

Given force that acts downward as 7.4N

∑Fy= Fy1+ Fy2 +Fy3 =0

Fy+ 5.9 sin 44° - 7.4= 0

F = 3.30 N

F =√Fₓ² +Fy²

= 5.37 N

b) angle of force= tan⁻¹ (3.30/-4.24)

= - 37.88°

To know more about force, refer

brainly.com/question/12970081

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2 years ago

A 40kg load is raised to a height of 25m. If the operation requires 1 min, find the power required

OlgaM077 [116]

Answer:

163.33 Watts

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 40 Kg

Height (h) = 25 m

Time (t) = 1 min

Power (P) =..?

Next, we shall determine the energy. This can be obtained as follow:

Mass (m) = 40 Kg

Height (h) = 25 m

Acceleration due to gravity (g) = 9.8 m/s²

Energy (E) =?

E = mgh

E = 40 × 9.8 × 255

E = 9800 J

Finally, we shall determine the power. This can be obtained as illustrated below:

Time (t) = 1 min = 60 s

Energy (E) = 9800 J

Power (P) =?

P = E/t

P = 9800 / 60

P = 163.33 Watts

Thus, the power required is 163.33 Watts

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3 years ago

A laser beam is incident at an angle of 33.0° to the vertical onto a solution of cornsyrup in water.(a) If the beam is refracted

IrinaK [193]

Answer:

1.29649

488.08706 nm

$6.14644\times 10^{14}\ Hz$

231715700.28346 m/s

Explanation:

n denotes refractive index

1 denotes air

2 denotes solution

$\lambda_0$ = 632.8 nm

From Snell's law we have the relation

$n_1sin\theta_1=n_2sin\theta_2\\\Rightarrow n_2=\dfrac{n_1sin\theta_1}{sin\theta_2}\\\Rightarrow n_2=\dfrac{1\times sin33}{sin24.84}\\\Rightarrow n_2=1.29649$

Refractive index of the solution is 1.29649

Wavelength is given by

$\lambda=\dfrac{\lambda_0}{n_2}\\\Rightarrow \lambda=\dfrac{632.8}{1.29649}\\\Rightarrow \lambda=488.08706\ nm$

The wavelength of the solution is 488.08706 nm

Frequency is given by

$f=\dfrac{c}{\lambda}\\\Rightarrow f=\dfrac{3\times 10^8}{488.08706\times 10^{-9}}\\\Rightarrow f=6.14644\times 10^{14}\ Hz$

The frequency is $6.14644\times 10^{14}\ Hz$

$v=\dfrac{c}{n_2}\\\Rightarrow v=\dfrac{3\times 10^8}{1.29469}\\\Rightarrow v=231715700.28346\ m/s$

The speed in the solution is 231715700.28346 m/s

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3 years ago

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3 years ago