Explanation:
As it is given that water level is same as outside which means that theoretically, P = 756.0 torr.
So, using ideal gas equation we will calculate the number of moles as follows.
PV = nRT
or, n = ![\frac{PV}{RT}](https://tex.z-dn.net/?f=%5Cfrac%7BPV%7D%7BRT%7D)
= ![\frac{\frac{756}{760}atm \times 0.129 L}{0.0821 Latm/mol K \times 298 K}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cfrac%7B756%7D%7B760%7Datm%20%5Ctimes%200.129%20L%7D%7B0.0821%20Latm%2Fmol%20K%20%5Ctimes%20298%20K%7D)
= 0.0052 mol
Also, No. of moles = ![\frac{mass}{\text{molar mass}}](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7B%5Ctext%7Bmolar%20mass%7D%7D)
0.0052 mol = ![\frac{mass}{2 g/mol}](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7B2%20g%2Fmol%7D)
mass = 0.0104 g
As some of the water over which the hydrogen gas has been collected is present in the form of water vapor. Therefore, at
= 24 mm Hg
=
atm
= 0.03158 atm
Now, P = ![\frac{756}{760} - 0.03158](https://tex.z-dn.net/?f=%5Cfrac%7B756%7D%7B760%7D%20-%200.03158)
= 0.963 atm
Hence, n =
= 0.0056 mol
So, mass of
= 0.0056 mol × 2
= 0.01013 g (actual yield)
Therefore, calculate the percentage yield as follows.
Percent yield = ![\frac{\text{Actual yield}}{\text{Theoretical yield}} \times 100](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%7BActual%20yield%7D%7D%7B%5Ctext%7BTheoretical%20yield%7D%7D%20%5Ctimes%20100)
=
= 97.49%
Thus, we can conclude that the percent yield of hydrogen for the given reaction is 97.49%.
Answer:
11.35 g/cm³
Explanation:
If your rounding then 11.4. hope this helps :)
Answer : The percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.
Explanation :
First we have to calculate the number of atoms in 5.5 wt% Pb and 94.5 wt% of Sn.
As, 207.2 g of lead contains
atoms
So, 5.5 g of lead contains
atoms
and,
As, 118.71 g of lead contains
atoms
So, 94.5 g of lead contains
atoms
Now we have to calculate the percent composition of Pb and Sn in atom.
![\% \text{Composition of Pb}=\frac{\text{Atoms of Pb}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100](https://tex.z-dn.net/?f=%5C%25%20%5Ctext%7BComposition%20of%20Pb%7D%3D%5Cfrac%7B%5Ctext%7BAtoms%20of%20Pb%7D%7D%7B%5Ctext%7BAtoms%20of%20Pb%7D%2B%5Ctext%7BAtoms%20of%20Sn%7D%7D%5Ctimes%20100)
![\% \text{Composition of Pb}=\frac{1.59\times 10^{22}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=3.21\%](https://tex.z-dn.net/?f=%5C%25%20%5Ctext%7BComposition%20of%20Pb%7D%3D%5Cfrac%7B1.59%5Ctimes%2010%5E%7B22%7D%7D%7B%281.59%5Ctimes%2010%5E%7B22%7D%29%2B%284.79%5Ctimes%2010%5E%7B23%7D%29%7D%5Ctimes%20100%3D3.21%5C%25)
and,
![\% \text{Composition of Sn}=\frac{\text{Atoms of Sn}}{\text{Atoms of Pb}+\text{Atoms of Sn}}\times 100](https://tex.z-dn.net/?f=%5C%25%20%5Ctext%7BComposition%20of%20Sn%7D%3D%5Cfrac%7B%5Ctext%7BAtoms%20of%20Sn%7D%7D%7B%5Ctext%7BAtoms%20of%20Pb%7D%2B%5Ctext%7BAtoms%20of%20Sn%7D%7D%5Ctimes%20100)
![\% \text{Composition of Sn}=\frac{4.79\times 10^{23}}{(1.59\times 10^{22})+(4.79\times 10^{23})}\times 100=96.8\%](https://tex.z-dn.net/?f=%5C%25%20%5Ctext%7BComposition%20of%20Sn%7D%3D%5Cfrac%7B4.79%5Ctimes%2010%5E%7B23%7D%7D%7B%281.59%5Ctimes%2010%5E%7B22%7D%29%2B%284.79%5Ctimes%2010%5E%7B23%7D%29%7D%5Ctimes%20100%3D96.8%5C%25)
Thus, the percent composition of Pb and Sn in atom is, 3.21 % and 96.8 % respectively.
Answer:
Hydrogen
Explanation:
Just to provide some background, an element is a pure substance consisting of only one type of atom. An atom is the smallest constituent of matter. All elements are comprised of a single type of atom (e.g., gold is composed of gold atoms, helium of helium atoms, phosphorus phosphorus, and so on).
A molecule is a group of two or more atoms. They can be the same atom (homonuclear), such as or different atoms (heteronuclear).
Some examples of homonuclear molecules include:
Hydrogen (H2)
Nitrogen (N2)
Phosphorus (P4)
Some examples of heteronuclear molecules include:
Carbon dioxide (CO2)
Sulfuric acid (H2SO4)
Methane (CH4)