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nika2105 [10]
3 years ago
12

A.16cm b. 16 root 2cm c. 8 root 2cm d. 8cm

Mathematics
1 answer:
Stolb23 [73]3 years ago
7 0

Answer:

C

Step-by-step explanation:

Mark as Brainliest :)

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Histogram would be right

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A New cell phone cost $225. The accessories cost 13% of the cell phone price. What is the cost of the accessories?
Anvisha [2.4K]
$29.25 use a calculator, 225 - 13% = 195.75, 225 - 195.75 = 29.25
3 0
3 years ago
What is cos (x)?<br><br> 48/58<br><br> 58/48<br><br> 26/58<br><br> 58/26
Evgen [1.6K]
<span>We have to calculate the length of the missing side.
Use the Pythagorean theorem:

a^2+32^2=58^2\\\\a^2+1024=3364\ \ \ |-1024\\\\a^2=2340\to a=\sqrt{2340}\\\\a=\sqrt{36\cdot65}\\\\a=6\sqrt{65}

\cos x=\dfrac{6\sqrt{65}}{58}=\dfrac{3\sqrt{65}}{29}

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8 0
3 years ago
The diagram shows a triangle.
Basile [38]

Answer:

s=13

Step-by-step explanation:

As\ we\ know\ that,\\"The \ sum\ of\ all\ angles\ of\ a\ triangle\ is\ 180"\\Hence,\\(4s+9)+(3s+1)+(6s+1)=180\\4s+3s+6s+9+1+1=180\\13s+11=180\\13s=180-11\\13s=169\\s=13

5 0
3 years ago
If AC=5cm, BC=12cm, and m AC= 40 degrees what is the radius of the circumscribed circle
melamori03 [73]
Let's assume they meant C=40 degrees.  With an angle like that they're asking for approximation; we'll oblige.

The circumradius is the product of the triangle sides divided by four times the area.

Here we have remaining side given by the Law of Cosines.

AB^2 = AC^2 + BC^2 - 2\ AC \ BC \cos C

AB^2 = AC^2 + BC^2  - 2 AC \ AB \cos C = 5^2 + 12^2 - 2(5)(12) \cos 40^\circ

AB = \sqrt{  169 - 120 \cos 40 ^\circ}  \approx 8.77921789

The area is \frac 1 2\ AC \ BC \sin C = \frac 1 2 (5)(12) \sin 40^\circ \approx 19.283628



The circumradius is  r \approx \dfrac{(5)(12)(8.77921789 )}{ 4 (19.283628) }  = 6.829019329




5 0
3 years ago
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