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3 years ago

How do newtons three laws of motion work

Physics

1 answer:

cricket20 [7]3 years ago

8 0

Answer:

The first law - The first law states that any object in motion will continue to move in the same direction and speed unless other forces act on it. For an example an apple starts rolling without any other forces interrupting it will roll forever.

The Second law - The second law says that the greater the mass of an object, the more force it will take to accelerate the object.

And lastly The Third law - "For every action, there is an equal and opposite reaction."

Explanation:

sources https://www.livescience.com/46558-laws-of-motion.html

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Una persona de 80 kg de masa corre a una velocidad cuya magnitud es de 9m/s. Cual es la magnitud de la cantidad de movimiento? Q

natka813 [3]

Responder:

13,01 m / s

Explicación:

Paso uno:

datos dados

masa de la persona 1 m = 80 kg

velocidad de la persona 1 v = 9 m / s

masa de la persona 2 M = 55kg

velocidad de la persona 2 v =?

Segundo paso:

la expresión del impulso se da como

P = mv

para la primera persona, el impulso es

P = 80 * 9

P = 720N

Paso tres:

queremos que la segunda persona tenga el mismo impulso que la primera, por lo que la velocidad debe ser

720 = 55v

v = 720/55

v = 13,09

v = 13,01 m / s

Por lo tanto, la magnitud de la velocidad debe ser 13.01 m / s.

4 0

2 years ago

A 50-g cube of ice, initially at 0.0°C, is dropped into 200 g of water in an 80-g aluminum container, both initially at 30°C.

MakcuM [25]

Answer:

b. 9.5°C

Explanation:

$m_i$ = Mass of ice = 50 g

$T_i$ = Initial temperature of water and Aluminum = 30°C

$L_f$ = Latent heat of fusion = $3.33\times 10^5\ J/kg^{\circ}C$

$m_w$ = Mass of water = 200 g

$c_w$ = Specific heat of water = 4186 J/kg⋅°C

$m_{Al}$ = Mass of Aluminum = 80 g

$c_{Al}$ = Specific heat of Aluminum = 900 J/kg⋅°C

The equation of the system's heat exchange is given by

$m_i(L_f+c_wT)+m_wc_w(T-T_i)+m_{Al}c_{Al}=0\\\Rightarrow 0.05\times (3.33\times 10^5+4186\times T)+0.2\times 4186(T-30)+0.08\times 900(T-30)=0\\\Rightarrow 1118.5T-10626=0\\\Rightarrow T=\dfrac{10626}{1118.5}\\\Rightarrow T=9.50022\ ^{\circ}C$

The final equilibrium temperature is 9.50022°C

4 0

3 years ago

A body accelerates uniformly from rest at 2m/s square. calculate it's velocity after traveling 9m.

Talja [164]

Answer:

6m/s

Explanation:

Given parameters:

Initial velocity = 0m/s

Acceleration = 2m/s²

Distance = 9m

Unknown:

Final velocity = ?

Solution:

To solve this problem, we use the expression below:

v² = u² + 2as

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance

v² = 0² + (2 x 2 x 9) = 36

v = 6m/s

3 0

2 years ago

A man pushes a 10kg box with a constant acceleration of 5m/s2. What force is applied to the box?

drek231 [11]

FORMULA

$\boxed {F = m \times a}$

F = force
m = mass
a = acceleration

Using the formula

$F = 10 \times 5$

Multiply

$\boxed {\textsf {F = 10 N}}$

8 0

2 years ago

Read 2 more answers

Your dog is running around the grass in your backyard. He undergoes successive displacements, 3.60 m south, 8.46 m northeast, an

Eduardwww [97]

First, we resolve the northeast displacement into its north and east components. The angle from the positive x-axis of a northeast displacement is 45 degrees. Thus:
North = 8.46sin(45) = 5.98 m
East = 8.46cos(45) = 5.98 m

North displacement = 5.98 - 3.6 = 2.38 m
West displacement = 15.6 - 5.98 = 9.62

Magnitude = √(2.38² + 9.62²)
Magnitude = 9.91 m

Direction:
tan∅ = 2.38 / 9.62
∅ = 13.9° north from east

3 0

2 years ago

Read 2 more answers