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Reptile [31]
3 years ago
13

How do newtons three laws of motion work

Physics
1 answer:
cricket20 [7]3 years ago
8 0

Answer:

The first law - The first law states that any object in motion will continue to move in the same direction and speed unless other forces act on it. For an example an apple starts rolling without any other forces interrupting it will roll forever.

The Second law - The second law says that the greater the mass of an object, the more force it will take to accelerate the object.

And lastly The Third law - "For every action, there is an equal and opposite reaction."

Explanation:

sources https://www.livescience.com/46558-laws-of-motion.html

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The electric company charges $0.08/kilowatt-hour. If a 2 kilowatt appliance is run for 3hours, how much will you have to pay to
asambeis [7]

Answer:

$ 0.48

Explanation:

We can calculate this quantity easily using successive products and taking into account the units.

\frac{0.08}{kw*h}*2[kw]*3[hr]\\ \\=0.48

The amount is $ 0.48

3 0
3 years ago
What are the structures shown below ??
forsale [732]
The body system on the chart
8 0
3 years ago
Sam receives the kicked football on the 3 yd line and runs straight ahead toward the goal line before cutting to the right at th
Pie

Answer:

Distance: 21 yd, displacement: 15 yd, gain in the play: 12 yd

Explanation:

The distance travelled by Sam is just the sum of the length of each part of Sam's motion, regardless of the direction. Initially, Sam run from the 3 yd line to the 15 yd line, so (15-3)=12 yd. Then, he run also 9 yd to the right. Therefore, the total distance is

d = 12 + 9 = 21 yd

The displacement instead is a vector connecting the starting point with the final point of the motion. Sam run first 12 yd straight ahead and then 9 yd to the right; these two motions are perpendicular to each other, so we can find the displacement simply by using Pythagorean's theorem:

d=\sqrt{12^2+9^2}=15 yd

Finally, the yards gained by Sam in the play are simply given by the distance covered along the forward-backward direction only. Since Sam only run from the 3 yd line to the 15 yd line along this direction, then the gain in this play was

d = 15 - 3 = 12 yd

7 0
3 years ago
In a scale model of the Solar System, if the Sun is represented by a ball with a diameter of about 8 inches, about how large wou
Evgesh-ka [11]

Answer:

size of popcorn seed may meet the scaled earth size of x = 0.07312 in.  

Explanation:

Given:-

- The diameter of actual sun, Ds = 1.3927 * 10^6 km

- The diameter of model sun ball, ds = 8 in

- The diameter of the actual earth, De = 12,742 km

Find:-

How large would be the earth model

Solution:-

- We can use the actual diameters of the earth and sun to develop the ratio of earth diameter to that of sun. The direct ratio can be used to model the diameter of earth for the scale model

                                          Sun                   Earth

                     Actual :     1392700 km     12,742 km

                      Scale :           8 in                    x

- Use direct relations and solve for x:

                               x = (8 in)*(12,742 km ) / ( 1392700 km )

                              x = 0.07312 in.

- From the given options apple, grapefruit and marble diameters are larger than 1 inch. So only the size of popcorn seed may meet the scaled earth size of x = 0.07312 in.  

4 0
3 years ago
Read 2 more answers
A cart of mass 6.0 kg moves with a speed of 3.0 m/s towards a second stationary cart with a mass of 3.0 kg. The carts move on a
IgorLugansk [536]

Answer:1.5

Explanation:

Given

mass of first  cart m_1=6 kg

initial Velocity u_1=3 m/s

mass of second cart m_2=3 kg

u_2=0 m/s

In the absence of External Force we can conserve momentum

m_1u_1+m_2u_2=(m_1+m_2)v

v=\frac{m_1u_1+m_2u_2}{m_1+m_2}

v=\frac{6\times 3+3\times 0}{6+3}

v=2 m/s

Final kinetic Energy of two masses

K.E._2=\frac{1}{2}(m_1+m_2)v^2

K.E._2=\frac{1}{2}\cdot (3+6)\cdot (2)^2

K.E._2=18 J

Initial Kinetic Energy

K.E._1=\frac{1}{2}m_1u_1^2+\frac{1}{2}m_2u_2^2

K.E._1=\frac{1}{2}6\times 3^2+0

K.E._1=27 J

ratio =\frac{K.E._1}{K.E._2}=\frac{27}{18}=1.5

5 0
3 years ago
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