20 g O2 x 1 mol O2/32 g O = 0.625 mol O2
Answer:
See Explanation
Explanation:
The equation of the reaction;
KHSO4(aq) + KOH(aq) -------> K2SO4(aq) + H2O(l)
Number of moles of KHSO4 = 49.6 g/136.169 g/mol = 0.36 moles
Since the reaction is in a mole ratio of 1:1, 0.36 moles of K2SO4 is produced.
Number of moles of KOH = 25.3 g/56.1056 g/mol = 0.45 moles
Since the reaction is 1:1, 0.45 moles of K2SO4 is produced
Hence K2SO4 is the limiting reactant.
Mass of K2SO4 formed = 0.36 moles of K2SO4 * 174.26 g/mol = 62.7 g
So;
1 mole of KHSO4 reacts with 1 mole of KOH
0.36 moles of KHSO4 reacts with 0.36 * 1/1 = 0.36 moles of KOH
Amount of excess KOH = 0.45 moles - 0.36 moles = 0.09 moles
Mass of excess KOH = 0.09 moles * 56.1056 g/mol = 5 g of excess KOH
Answer:
Determine how many formula units are in 2.35 moles of lithium phosphite?
Explanation:
After reading the sources provided write a 250 word summary on the contributions of West Virginians to the war effort.What are the dimensions of the product? 2 6 4 1 -3 0 x -3 -2 -8 2 3 5 1 x 2 2 x 2 3 x 2 3 x 3Can somebody help me with this pleaseDetermine how many formula units are in 2.35 moles of lithium phosphite?Can someone help? It's due todayWhat main idea links all three of the article excerpts contained in th passage together? A) Taxation rates should be applied equally and fairly to all people. B A little bit of kindness goes a long way in trying to change the world. C) No one deserves to be lonely, and everyone deserves to be loved. D African-Americans had to fight long and hard to receive equal rights in America.Can somebody help me with this pleaseCan somebody help me with this pleaseAfter reading the sources provided write a 250 word summary on the contributions of West Virginians to the war effort.
Answer:
SO… The larger wire looses heat energy faster, however the smaller wire decreases temperature faster. ... Their surface area is much larger in proportion to their body mass and they lose heat through their skin when it is cold and they gain heat through their skin when it is hot much faster than an adult does.
Explanation:
Answer:
ΔG = - 442.5 KJ/mol
Explanation:
Data Given
delta H = -472 kJ/mol
delta S = -108 J/mol K
So,
delta S = -0.108 J/mol K
delta Gº = ?
Solution:
The answer will be calculated by the following equation for the Gibbs free energy
G = H - TS
Where
G = Gibbs free energy
H = enthalpy of a system (heat
T = temperature
S = entropy
So the change in the Gibbs free energy at constant temperature can be written as
ΔG = ΔH - TΔS . . . . . . (1)
Where
ΔG = Change in Gibb’s free energy
ΔH = Change in enthalpy of a system
ΔS = Change in entropy
if system have standard temperature then
T = 273.15 K
Now,
put values in equation 1
ΔG = (-472 kJ/mol) - 273.15 K (-0.108 KJ/mol K)
ΔG = (-472 kJ/mol) - (-29.5 KJ/mol)
ΔG = -472 kJ/mol + 29.5 KJ/mol
ΔG = - 442.5 KJ/mol
