Answer:
the average net force on the truck is 3744 N.
Explanation:
Given;
mass of the truck, m = 1200 kg
initial velocity of the truck, u = 25 m/s
final velocity of the truck, v = 53 m/s
distance traveled by the truck, d = 350 m
The acceleration of the truck is calculated as;
v² = u² + 2ad
53² = 25² + (2 x 350)a
700a = 53² - 25²
700a = 2184
a = 2184 / 700
a = 3.12 m/s²
The average net force on the truck is calculated as;
F = ma
F = 1200 x 3.12
F = 3744 N
Therefore, the average net force on the truck is 3744 N.
To calculate the final velocity, we use Newton's first equation of linear motion:v=u+at
Where v is final velocity
u is initial velocity
a is the average acceleration
t is the time taken during acceleration.
Therefore,
v=0+2.5m/s²*6.00s
=15m/s
Decelerating from 15m/s;
v=15m/s+(-2m/s²×4.0s)
=3m/s
To get the distance it travelled, we use
v²=u²+2as
During acceleration, the distance travelled is calculated as below.
15²=0+2×2.5S
225=5S
S=45meters
During decellaration, displacement is calculated as below,
3²=15²+(2×4S)
9=225+8S
8S=216
S=27meters
Total displacement=45m+27m
=72 meters.
Explanation:
The given data is as follows.
mass (m) = 5 kg
Height of tower = 15 m
u = 7 m/s
air resistance = 610 v
(a) Now, differential equation for the given mass which is thrown vertically upwards is as follows.
= F
-bv = Fr
Here, mg is downwards due to the force of gravity.
= 0
Hence, the differential equation required to solve the problem is as follows.
= 0
(b) When final velocity of the object is equal to zero then the object will reach towards its maximum height and it will start to fall downwards.
F =
= 0
Therefore, the object reach its maximum height at v = 0.
Answer:
1.038s
Explanation:
To solve this problem we use the following equation for the free fall movement:
where is the height, is the initial velocity, in this case since the rock was just dropped, , is the acceleration of gravity of the planet in this case mars, thus g will be: . And is time, wich is what we are looking for.
Clearing the equation for :
since
we have and from the problem we have that
thus:
The time it takes is 1.038s