Write an inequality to represent the situation. Then determine if 36 is a possible solution.

Mathematics

1 answer:

viva [34]3 years ago

4 0

Answer:

T≥35. 36 is a possible solution.

Step-by-step explanation:

Atleast means that the number indicated is included thus a greater than or equal to sign is used.

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The graph represents the function (check picture)

Taya2010 [7]

Answer:

a = 1 and b = -12

Step-by-step explanation:

* Lets look to the graph to solve the problem

- f(x) is a rational function with:

# numerator ⇒ x² - 4x + 3

# denominator ⇒ x² + ax + b

- To find the values of a and b lets use the hole and the vertical

asymptote in the graph of the function

∵ There is a hole at x = 3

- The hole appears when the numerator and the denominator have

a common factor

∵ x = 3 ⇒ subtract 3 from both sides

∴ x - 3 = 0

∴ The numerator and the denominator have a factor (x - 3)

- The vertical asymptotes appear at the zeros of the denominator

that means the values of x when the denominator = 0

∵ There is a vertical asymptote at x = -4

∵ x = -4 ⇒ add 4 for both sides

∴ x + 4 = 0

∴ The denominator has another factor (x + 4)

- The denominator x² + ax + b has two factors (x - 3) and (x + 4) lets

multiply them to find the value of a and b

∵ (x - 3)(x + 4) = (x)(x) + (x)(4) + (-3)(x) +(-3)(4)

∴ (x - 3)(x + 4) = x² + 4x - 3x - 12 = x² + x - 12

∴ x² + ax + b = x² + x - 12

- By comparing the two sides

∴ a = 1 and b = -12

8 0

3 years ago

The formula to find the period of orbit of a satellite around a planet is (T^2) = (4pi^2/ gm) r3 where r is the orbit’s mean rad

Inga [223]

See the attached graphic to see this solved for "r".
You should be very careful about stating the units for each of those variables.
time in seconds
radius in meters
mass in kilograms
G = 6.674 x 10^-11 m^3 / (kilograms * seconds²)
Also, it would be worth your while to go to this web page http://www.1728.org/kepler3a.htm
It has a calculator and other information about Kepler's Third Law.