Acceleration = V/t
First set velocity to m/s
V = 72.42 m/s
Now we divide velocity by time
A = 72.42/39.5
A = 1.83 m/s^2
The current is defined as the quantity of charge Q that passes through a certain location in a time
:
Using the data of the problem, we find:
Answer:
A scientific model is a way of representing a system to better understand it's behavior
Explanation:
For the first part, we are looking for Vf when dy=11.0
Upward is positive, downward is negative.
So <span>Vf = square root [2(-9.8)(11.0) + (18.0)^2] </span>
<span>Vf = 10.4 m/s your answer is correct.
For the part b, t is equals to the time took to reach and dy is equals to 11.0
you did, </span>11= 18t m/s-(1/2) 9.8t^2 then <span>-11 + 18t- 9.8t^2. By quadratic formula, for the way down the answer is 2.9 s while on it's way up, the answer is 0.77 s</span><span>
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