Answer: I am pretty sure it is (b) what is the value of mass suspended at the end of the spring.
Explanation:
Answer:
d' = 75.1 cm
Explanation:
It is given that,
The actual depth of a shallow pool is, d = 1 m
We need to find the apparent depth of the water in the pool. Let it is equal to d'.
We know that the refractive index is also defined as the ratio of real depth to the apparent depth. Let the refractive index of water is 1.33. So,

or
d' = 75.1 cm
So, the apparent depth is 75.1 cm.
The answers to the problem are as follows:
MA= 5
IMA= input distance/ output distance, 5
<span>AMA= output force/ input force, 5/2
</span>
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