Question

In a double slit experiment, 450 nm light passes through two slits producing an interference pattern where the first bright fringe on a distant screen is 0.2° from the central fringe. What is the slit separation? g

Answer 1

Answer:

1.3 x 10⁻⁴ m

Explanation:

$\lambda$ = wavelength of the light = 450 nm = 450 x 10⁻⁹ m

n = order of the bright fringe = 1

θ = angle = 0.2°

d = separation between the slits

For bright fringe, Using the equation

d Sinθ = n $\lambda$

Inserting the values

d Sin0.2° = (1) (450 x 10⁻⁹)

d (0.003491) = (450 x 10⁻⁹)

d = 1.3 x 10⁻⁴ m