<u>Answer:</u>
<em>Chemistry is the reaction between certain elements to </em><em>create a new compound</em><em> which may happen naturally but is mostly man made and hence has lot of good as well as </em><em>adverse effects.</em>
<u>Explanation:</u>
The <em>product or compound</em> that we get and the energy or outcome we receive is the ultimate result that decides whether chemical reaction that has happened is good or bad.
There are reactions that may cause pain and suffering to living beings and are also able to<em> Infuse damage and destruction</em> are are adverse nature. they can also change the course of nature hence are are <em>dangerous.
</em>
C. a scientific approach to answering questions
Answer : Option (A) Accelerator 2 model has the lowest percentage of energy lost as waste.
Solution : Given,
For Accelerator 1 model,
Input energy = 2078.3 J
Wasted energy = 663.1 J
Output energy = 1415.2 J
For Accelerator 2 model,
Input energy = 7690.0 J
Wasted energy = 2337.5 J
Output energy = 5353.5 J
For Accelerator 3 model,
Input energy = 4061.9 J
Wasted energy = 2259.6 J
Output energy = 1802.3 J
Formula used for lowest percentage of energy lost as waste is:
% energy lost as waste = (Total energy wasted / Total input energy ) × 100
For Accelerator 1 model,
% energy lost as waste =
= 31.90%
For Accelerator 2 model,
% energy lost as waste =
= 30.39%
For Accelerator 3 model,
% energy lost as waste =
= 55.62%
So, we conclude that the Accelerator 2 model has the lowest percentage of energy lost as waste.
This name tells us that the molecule has three carbons and has a double bond in it.
pro means three carbons when talking about hydrocarbons
ene means the presence of at least 1 double bond
ane means all single bonds and yne means at least one triple bond which means that propane is a three carbon molecule with only single bonds connecting them while propyne has three carbons with a triple bond between 2 of the carbons.
I hope this helps. Let me know if anything is unclear.
Answer:

Explanation:
In this problem we only have information of the equilibrium, so we need to find a expression of the free energy in function of the constant of equilireium (Keq):

Being Keq:
![K_{eq}=\frac{[fructose][Pi]}{[Fructose-1-P]}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5Bfructose%5D%5BPi%5D%7D%7B%5BFructose-1-P%5D%7D)
Initial conditions:
![[Fructose-1-P]=0.2M](https://tex.z-dn.net/?f=%5BFructose-1-P%5D%3D0.2M)
![[Fructose]=0M](https://tex.z-dn.net/?f=%5BFructose%5D%3D0M)
![[Pi]=0M](https://tex.z-dn.net/?f=%5BPi%5D%3D0M)
Equilibrium conditions:
![[Fructose-1-P]=6.52*10^{-5}M](https://tex.z-dn.net/?f=%5BFructose-1-P%5D%3D6.52%2A10%5E%7B-5%7DM)
![[Fructose]=0.2M-6.52*10^{-5}M](https://tex.z-dn.net/?f=%5BFructose%5D%3D0.2M-6.52%2A10%5E%7B-5%7DM)
![[Pi]=0.2M-6.52*10^{-5}M](https://tex.z-dn.net/?f=%5BPi%5D%3D0.2M-6.52%2A10%5E%7B-5%7DM)


Free-energy for T=298K (standard):

