Answer:
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Explanation:
The rate of increase of NH3 is 0.22M/s.
<h3>What is the balanced equation of the reaction?</h3>
The balanced equation of the reaction is given below:
- N2(g) + 3 H2(g) → 2 NH3(g)
The rate of decrease of N2 is half the rate of increase of NH3.
Rate of decrease of N2 = -0.11 M/s
Rate of increase of NH3 = 2 × +0.11 M/s = 0.22M/s.
In conclusion, the rate of formation of products is dependent on the rate of disappearance of reactants.
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Answer:
The reactant/reagent that would be most atom economical is EtI (Ethy Iodide) and KOH (potassium oxide) as base
This is because the iodo group are weak base hence they have a good leaving character (i.e they are unstable on their own ) which would increase the rate of reaction and the strong base KOH give the most atom economical
Explanation:
Answer: The first isotope has a relative abundance of 79% and last isotope has a relative abundance of 11%
Explanation: Given that the average atomic mass(M) of magnesium
= 24.3050amu
Mass of first isotope (M1) = 23.9850amu
Mass of middle isotope (M2)=24.9858amu
Mass of last isotope(M3)= 25.9826amu
Total abundance = 1
Abundance of middle isotope = 0.10
Let abundance of first and last isotope be x and y respectively.
x+0.10+y =1
x = 0.90-y
M = M1 × % abundance of first isotope + M2 × % of middle isotope +M3 ×% of last isotope
24.03050= 23.985× x + 24.9858 ×0.10 + 25.9826×y
Substitute x= 0.90-y
Then
y = 0.11
Since y=0.11, then
x= 0.90-0.11
x=0.79
Therefore the relative abundance of the first isotope = 11% and the relative abundance of the last isotope = 79%
