Answer: Flexible duct because, They also developed more than 1,000 safety criteria, some of which are... labelled goods bearing a silver UL sticker on the duct that defines this listing. ... lie in the research carried out by UL and, as a result, the authorized use of the code. Air Ducts are required to perform 15 separate tests.
Source: https://dundasjafine.com/ul-classification/
Answer:
a) 4-input XOR, input data-1001 = 0 Even parity Bit
b) 5-input XOR, input data-10010 = 0 Even parity Bit
c) 6-input XOR, input data-101001 = 1 Even parity Bit
d) 7-input XOR, input data 1011011 = 1 Even parity Bit
Explanation:
a) 4-input XOR, input data-1001 ; generates 0 Even parity Bit
b) 5-input XOR, input data-10010 ; generates 0 Even parity Bit
c) 6-input XOR, input data-101001 ; generates 1 Even parity Bit
d) 7-input XOR, input data 1011011 ; generates 1 Even parity Bit
Attached below is the Logic circuits of the data inputs
Answer:
676 ft
Explanation:
Minimum sight distance, d_min
d_min = 1.47 * v_max * t_total where v_max is maximum velocity in mi/h, t_total is total time
v_max is given as 50 mi/h
t_total is sum of time for right-turn and adjustment time=8.5+0.7=9.2 seconds
Substituting these figures we obtain d_min=1.47*50*9.2=676.2 ft
For practical purposes, this distance is taken as 676 ft
Answer:
0.65 m/min
Explanation:
The volume of material to be removed is
80*8*10 = 650 cm^3
The tool has a diameter of 4 mm and a maximum axial cutting capacity of 50 mm, so its cross section normal to advance is
0.4*5 = 2 cm^2
If the groove have to be made in T = 5 minutes the advance speed would be
V/(S * T)
650/(2 * 5) = 65 cm/min = 0.65 m/min
Answer: (a) 0,142 (b) 52.99 (c) 2.83 (d) 88.26
Explanation:
If the refrigarating capacity is 150kw
(a) the mass flow rate of refrigerant, in kilograms per second is 0.142
(b) the power input to the compressor, in kilowatts is 52.99
(c) the coefficient of performance is 2.83
(d) the isentropic compressor efficiency is 68.6 per cent
