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2 years ago

1. What's the maximum overall length of the part? 2. What material is used to fabricate the part

Engineering

1 answer:

kiruha [24]2 years ago

8 0

Answer:

1. The maximum length overall length of the part is 4 inches

2. The material with which the part is fabricated is 0.25 inch thick Hot Rolled Steel

Explanation:

The information given in the drawing are;

The angle of projection of the drawing = Third angle projection

The thickness of the material = 0.25" plate

The material with which the part is fabricated = 0.25 inch thick HRS

HRS is the acronym for Hot Rolled Steel

Therefore;

The material with which the part is fabricated is 0.25 inch thick Hot Rolled Steel

The scale of the drawing = 1:1 = which is 1 is to 1 drawing

The maximum length overall length of the part, l = 4 units

By visually testing the 1:1 scale drawing measurements of 4 units is comparable 4 inches measurement with an online ruler

Therefore;

The maximum length overall length of the part, l = 4 inches

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castortr0y [4]

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This indicates that the threshold voltage is lower for the green LED light than the blue.

Explanation:

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2 years ago

A program is seeded with 30 faults. During testing, 21 faults are detected, 15 of which are seeded faults and 6 of which are ind

Vesna [10]

Answer:

Estimated number of indigenous faults remaining undetected is 6

Explanation:

The maximum likelihood estimate of indigenous faults is given by,

$N_F=n_F\times \frac{N_S}{n_S}$ here,

$n_F$ = the number of unseeded faults = 6

$N_S$ = number of seeded faults = 30

$n_s$ = number of seeded faults found = 15

So NF will be calculated as,

$N_F=6\times \frac{30}{15}=12$

And the estimate of faults remaining is $N_F-n_F$ = 12 - 6 = 6

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3 years ago

How will the delay and active power per device change as you increase the doping density of both the N- and the P-MOSFET?

Murljashka [212]

Answer:

hello your question is incomplete attached below is the missing part of the question

Consider an inverter operating a power supply voltage VDD. Assume that matched condition for this inverter. Make the necessary assumptions to get to an answer for the following questions.

answer : Nd ∝ rt

Explanation:

Determine how the delay and active power per device will change as the doping density of N- and P-MOSFET increases

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Pactive = $\frac{q^2Nd^2*Xn^2}{6Eo} * f$

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3 years ago

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Answer:

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Explanation:

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3 years ago

A single fixed pulley is used to lift a load of 400N by the application of an effort of 480N in 10s through a vertical height of

Allushta [10]

Answer:

(a) the velocity ratio of the machine (V.R) = 1

(b) The mechanical advantage of the machine (M.A) = 0.833

Explanation:

Given;

load lifted by the pulley, L = 400 N

effort applied in lifting the, E = 480 N

distance moved by the effort, d = 5 m

(a) the velocity ratio of the machine (V.R);

since the effort applied moved downwards through a distance of d, the load will also move upwards through an equal distance 'd'.

V.R = distance moved by effort / distance moved by the load

V.R = 5/5 = 1

(b) The mechanical advantage of the machine (M.A);

M.A = L/E

M.A = 400 / 480

M.A = 0.833

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2 years ago