Answer:
a) The mass flow rate of water is 14.683 kilograms per second.
b) The pressure difference across the pump is 245.175 kilopascals.
Explanation:
a) Let suppose that pump works at steady state. The mass flow rate of the water (
), in kilograms per second, is determined by following formula:
(1)
Where:
- Pump power, in watts.
- Efficiency, no unit.
- Gravitational acceleration, in meters per square second.
- Hydrostatic column, in meters.
If we know that
,
,
and
, then the mass flow rate of water is:
![\dot m = 14.683\,\frac{kg}{s}](https://tex.z-dn.net/?f=%5Cdot%20m%20%3D%2014.683%5C%2C%5Cfrac%7Bkg%7D%7Bs%7D)
The mass flow rate of water is 14.683 kilograms per second.
b) The pressure difference across the pump (
), in pascals, is determined by this equation:
(2)
Where
is the density of water, in kilograms per cubic meter.
If we know that
,
and
, then the pressure difference is:
![\Delta P = 245175\,Pa](https://tex.z-dn.net/?f=%5CDelta%20P%20%3D%20245175%5C%2CPa)
The pressure difference across the pump is 245.175 kilopascals.