Answer:
true
Explanation:
true An electromagnet is formed when a coil of wire wrapped around an iron core is hooked up to a dry cell battery. The current traveling through the wire sets up a magnetic field around the wire. TRUE or FALSE
The statement that correctly describes the circuit is the circuit provided is an example of a CMOS circuit.
<h3>What is a CMOS circuit?</h3>
The CMOS circuit is a term that is often known as "Complementary Metal Oxide Semiconductor."
This is known to be a machine that create integrated circuits and it is one that is often seen a a lot of electronic component and as such, the the circuit provided is an example of a CMOS circuit.
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Answer:
V = 6.33 m/s
Explanation:
Given:
- The length of the wire L = 0.02 m
- The diameter of the wire D = 0.0005 m
- The calibration expression V = 0.0000625*h^2
- Environment temperature T_inf = 298 K
- Surface temperature T_s = 348 K
- The voltage drop dV = 5 V
- The electric current I = 0.1 A
Find:
- the velocity of Air
Solution:
- Calculate the surface area of the wire:
A = pi*D*L
A = pi*(0.0005)*(0.02) = 0.00003142 m^2
- The rate of energy in the wire P:
P = I*dV = 0.1*5 = 0.5 W
- Apply Newton's Law of Cooling:
P = h*A*(T_s - T_inf)
h = P /A*(T_s - T_inf)
Plug in the values:
h= 0.5/ 0.00003142*(348 - 298)
h = 318.27 W /m^2K
- Using the calibration relationship given, compute the velocity of air:
V = 6.25*10^-5 * h^2
V = 6.25*10^-5 * (318.27)^2
V = 6.33 m/s
Answer:
the jig grinder provides more precise x- and y-axis movements than a vertical milling machine for extremely accurate positioning
Answer:
The required rated input apparent power is 14.98 HP
Explanation:
Real power input = real power output ÷ efficiency
real power output = 12 HP
efficiency = 90% = 0.9
Real power input = 12 ÷ 0.9 = 13.33 HP
Apparent power input = real power input ÷ power factor = 13.33 ÷ 0.89 = 14.98 HP
