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SVETLANKA909090 [29]
3 years ago
14

An op-amp differential amplifier is built using four identical resistors, each having a tolerance of ±5%. Calculate the worst p

ossible CMRR.
Engineering
1 answer:
MatroZZZ [7]3 years ago
4 0

Answer:

80.9 db.

Explanation:

So, in this particular Question/problem we need to determine/calculate for the the worst possible CMRR. The data or information provided by the Question above;

=> ''amp differential amplifier is built using four identical resistors''

Therefore, R1 = R2 = R3 = R4. From the question above, we also know that the tolerance is ±5% for resistor that is;

A1 = A2 = A3 = A4 = A ±5%.

Using the kirchoff formula to each case, we have;

(1). Non Inverting terminal:

[ J - J2 / (A1 = A3) ] + J/ (A2 = A4) = 0.

J = 0.53 J2.

(2). Inverting terminal:

[ J_ - J2 / (A1 = A3) ] + J_ - Jb / (A2 = A4) = 0.

Thus, Jb = 2.11 J_ - 1.11 J2.

Note that J = J_ = 0.53 J2.

Thus, Jb = 1.11 J2 - 1.11 J1.

(Note that we will have that A2 = A4 = A + 0.05 = 1.05A.

Also, A1 = A3 = A - 0.05 = 0.95A).

The voltage is c1 and c2.

Therefore, Jb = 1.11( ccm + cv/2) - 1.11 ( Ccm - cv/2).

= - 10^-4 ccm - 1.11 cv.

Thus, CMMR = 20 log [| 1.11 ÷ (- 10^-4)|] = 80.9 db.

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A water pump delivers 3 hp of shaft power when operating. If the pressure differential between the outlet and the inlet of the p
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Answer:

Mechanical Efficiency =  83.51%

Explanation:

Given Data:

Pressure difference = ΔP=1.2 Psi

Flow rate = V=8ft^3/s\\

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Required:

Mechanical Efficiency

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We will first bring the change the units of given data into SI units.

P=1.2*6.895 = 8.274KPa\\V=8*0.00283=0.226 m^3/s\\P=3*0.746=2.238KW

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=(Mass * change in P)/density\\= \frac{M*P}{p}\\\\

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substituting the value

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Answer:

Follows are the solution to this question:

Explanation:

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\to a= \frac{dv}{dt}

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\to \frac{dv}{ds} =\frac{4 \frac{m}{s^2}}{43.59 \frac{m}{s}} \\\\

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