Answer:
Because of the formula
Explanation:
In this problem we are describing two different processes:
- Nuclear fission occurs when a heavy, unstable nucleus breaks apart into two or more lighter nuclei
- Nuclear fusion occurs when two (or more) light nuclei fuse together producing a heavier nucleus
In both cases, the total mass of the final products is smaller than the total mass of the initial nuclei.
According to Einsten's formula, this mass difference has been converted into energy, as follows:
where:
E is the energy released in the reaction
is the mass defect, the difference between the final total mass and the initial total mass
is the speed of light
From the formula, we see that the factor is a very large number, therefore even if the mass defect is very small, nuclear fusion and nuclear fission release huge amounts of energy.
Its a, metal is a good conductor of heat so yea
Hope this helps :)
Answer:
c. the speed of a planet is greatest when it is closest to the Sun.
Explanation:
Johannes Kepler was an astronomer who discovered that planets had elliptical orbits in the early 1600s (between 1609 and 1619).
The three (3) laws published by Kepler include;
I. The first law of planetary motion by Kepler states that, all the planets move in elliptical orbits around the Sun at a focus.
II. According to Kepler's second law of planetary motion, the speed of a planet is greatest when it is closest to the Sun.
Thus, the nearer (closer) a planet is to the Sun, the stronger would be the gravitational pull of the sun on the planet and consequently, the faster is the speed of the planet in terms motion.
III. The square of any planetary body's orbital period (P) is directly proportional to the cube of its orbit's semi-major axis.
This aint even a question
Answer:
Explanation:
We shall find first the distance where electric field is E/4 .
Let the charge be Q and distance be d where electric field is E . From the coulomb's Law
E = k Q / d²
Let distance be d₁ where field is E/4
E/4 = kQ / d₁²
Dividing the two equation
4 = d₁² / d²
d₁ = 2d
We shall have to find Potential at d₁ which is equal to 2 d .
Potential at d₁
V = k Q / 2d
= kQ d / 2d²
= E d / 2 . where d is distance of the point where field is E .