Answer:
45.09 m/s^2
Explanation:
from the question we were given the following parameters
mass = 931.9 kg
initial velocity (V1) = 0 m/s ( since it started from rest )
final velocity (V2) = 25.7 m/s
time (t) = 0.57 s
The average acceleration is given by:
a = ( V2 - V1 ) / t
therefore
a = (25.7 - 0) / 0.57 = 45.09 m/s^2
Answer:
= 4
Explanation:
To solve this exercise we will use Bohr's atomic model
= - 13.606 / n² [eV]
The transition from level n = 2 to level n = 1 is valid
= - 13.606 [¼ -1/1]
= 10.2045 eV
Bohr's model for atoms with only one electron is
= -13.606 Z² / n²
Where Z is the atomic number of the atom.
In this case the helium atom has an atomic number of Z = 2 from the level n₀ = 2 let's look up to what level it reaches
ΔE = -13.606 [4 /
² - 4/4]
4 /
² = -ΔE / 13.606 + 1
4 /
² = -10.2045 / 13.606 +1 = -0.75 +1
4 /
² = 0.25
= √ 4 / 0.25
= 4
Answer: option A) initially increases, then decreases.
Justification:
The increase of the rate of effective collisions among particles as the temperature increases is explained by the collision theory in virtue of the increase of the kinetic energy.
This is, as the temperature increase so the kinetic energy increase and the higher the kinetic energy the greater the number of collisions and the greater the chances that this energy overcome the activation energy (the energy needed to start the reaction).
Now, as the reaction progress the number of reactants particles naturally decrease (some of them have been converted into product) so this lower number of particles means lower concentration which means lower collisions and, thereafter, a decrease in the reaction rate.
The answer is Anguer...
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