What is the displacement of a student who walks 12 m North, 5 m West, 3 m South,
1 answer:
When you draw all 4 of those moves, you see that he winds up 9m North and 11m West of where he started.
So the magnitude of his displacement is
D = √(9² + 11²) m²
D = √(81 + 121) m²
D = √(202) m²
<em>D = 14.2 m</em>
The direction is arctan(-11/9) = <em>50.7° west of North</em>
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