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Answer : The formula of the gas produced is, (phosphine gas)
Explanation :
According to the question, when sodium phosphide is treated with water then it react to give phosphine gas and sodium hydroxide.
The balanced chemical reaction will be:
By Stoichiometry of the reaction we can say that:
1 mole of sodium phosphide reacts with 3 moles of water to give 1 mole of phosphine gas and 3 moles of sodium hydroxide.
Thus, the formula of the gas produced is, (phosphine gas)
Answer:
1.7927 mL
Explanation:
The mass of solid taken = 4.75 g
This solid contains 21.6 wt% , thus,
Mass of =
= 1.026 g
Molar mass of = 261.337 g/mol
The formula for the calculation of moles is shown below:
Thus,
Considering the reaction as:
1 moles of react with 1 mole of
Thus,
0.003926 mole of react with 0.003926 mole of
Moles of = 0.003926 mole
Also, considering:
Molarity = 2.19 M
So,
Volume = 0.0017927 L
Also, 1 L = 1000 mL
<u>So, volume = 1.7927 mL</u>