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Olegator [25]
3 years ago
8

1)

Chemistry
1 answer:
sweet [91]3 years ago
5 0

Answer:

Chemical reactions, chemistry, science as inquiry and data analysis. ... Students burn steel wool in both an open and closed environment to understand ... The difference in mass for this small sample of steel wool will be very small. ... careful attention to the balloon! 9. When rusting occurs the properties of the metal changes.

Explanation:

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When the submarine's density is equal to the density of the surrounding seawater, the submarine will maintain depth. If a 103200
GaryK [48]

Answer:

2.023 m^3 is the total displacement (volume) of the submarine.

Explanation:

Mass of water carried by submarine at 1000 ft depth = m = 2100 kg

The density of seawater at 1000 ft depth = d = 1033 kg/m^3

Volume of the water displaced = V= ?

Total displacement of the submarine = Volume of the water displaced = V

Density=\frac{Mass}{Volume}

V=\frac{m}{d}=\frac{2100 kg}{1033 kg/m^3}=2.023 m^3

2.023 m^3 is the total displacement (volume) of the submarine.

6 0
2 years ago
What number of atoms of phosphorus are present in 1.00g of each of the compounds in exercise 40?
ira [324]

Answer:

Answer: 1.095 * 10^22 atoms of P.

Explanation:

3 0
2 years ago
How many moles of potassium nitrate, KNO3 are present in a sample with a mass of 85.2 g?
Bingel [31]
0.843 moles would be the answer
5 0
3 years ago
How many moles are in 9.50 x 1022 molecules of CO? Be sure to ALL work below and report your answer using the correct number of
eimsori [14]

Answer:

0.158 moles

Explanation:

We are given;

9.50 x 10^22 molecules of CO

We are required to determine the number of moles;

We need to know;

1 mole of a compound = 6.022 × 10^23 molecules

Therefore;

9.50 x 10^22 molecules of CO will be equivalent to;

= 9.50 x 10^22 molecules ÷ 6.022 × 10^23 molecules/mole

= 0.158 moles

Therefore, the number of moles are 0.158 moles

4 0
3 years ago
PLEASE HELP ASAP PLEASE
USPshnik [31]

Answer:

<em>If it served you, give me 5 stars please, thank you!</em>

<em />

<em>m = </em><u><em>25</em></u><em> </em><em> </em><u><em>Kg</em></u>

8 0
3 years ago
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