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Olegator [25]
2 years ago
8

1)

Chemistry
1 answer:
sweet [91]2 years ago
5 0

Answer:

Chemical reactions, chemistry, science as inquiry and data analysis. ... Students burn steel wool in both an open and closed environment to understand ... The difference in mass for this small sample of steel wool will be very small. ... careful attention to the balloon! 9. When rusting occurs the properties of the metal changes.

Explanation:

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What happens to the DNA during interphase?
sweet [91]

interphase refers to: all stages of the cell cycle other than mitosis. During interphase, cellular organelles double in number, the DNA replicates, and protein synthesis occurs. The chromosomes are not visible and the DNA appears as uncoiled chromatin.

7 0
3 years ago
Read 2 more answers
Iridium has only two naturally occurring isotopes. The mass of iridium-191 is 190.9605 amu and the mass of iridium-193 is 192.96
cluponka [151]

Answer:

Abundance of Iridium-193 is 62.75%

Explanation:

From the question given above, the following data were obtained:

Isotope A (Iridium-191):

Mass of A = 190.9605 amu

Abundance of A = A%

Isotope B (Iridium-193):

Mass of B = 192.9629 amu

Abundance B = (100 – A) %

Relative atomic mass of Iridium = 192.217 amu

Next, we shall determine the abundance of isotope A (Iridium-191). This can be obtained as follow:

Relative atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]

192.217 = [(190.9605 × A%)/100] + [(192.9629 × (100 – A)%)/100]

192.217 = 1.909605A% + 1.929629(100 – A)%

192.217 = 1.909605A% + 192.9629 – 1.929629A%

Collect like terms

192.217 – 192.9629 = 1.909605A% – 1.929629A%

–0.7459 = –0.020024A%

Divide both side by –0.020024

A% = –0.7459 / –0.020024

A% = 37.25 %

Finally, we shall determine the abundance of Isotope B (Iridium-193).

This can be obtained as follow:

Abundance of A (Iridium-191) = 37.25 %

Abundance of B (Iridium-193) =?

Abundance B = 100 – A%

Abundance B = 100 – 37.25 %

Abundance of B (Iridium-193) = 62.75%

4 0
2 years ago
How many grams of NaOH are needed to neutralize 50 grams of H2SO4
slavikrds [6]

Answer:

H2SO4 + 2NaOH ==> Na2SO4 + 2H2O

Explanation:

8 0
2 years ago
Read 2 more answers
(34.6785 x 5.39) + 435.12
Shalnov [3]
To solve this, we should follow order of operations. To start, we should multiply the values inside of the parentheses.

(34.6785*5.39)+435.12
186.917115+435.12

Now, we should add the 2 values we are left with together.

 186.917115
<span><u>+435.120000</u>
</span>  622.037115

Using the math above, we can see that this expression is equal to 622.037115.
5 0
3 years ago
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Which reaction would most likely occur at the cathode of an electrochemical cell?
JulijaS [17]

Answer:

D

Explanation:

D

5 0
3 years ago
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