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3 years ago

The structure of DNA resembles a twisted ladder. Determine the structural components that form the rungs of the ladder.

2 answers:

8 0

Answer: Nitrogenous bases guanine(G), adenine(A), cytosine(C) and thymine(T) forms the rungs of the ladder in twisted ladder structure of DNA.

Explanation:

Rungs of the ladder are normally horizontal small logs placed one after the other with small gaps between them on the two vertically standing logs of the ladder.

Since, DNA resembles the twisted ladder structure the rungs of the ladder structure of DNA are the organic nitrogenous basic molecules which are associated to their respective base with the help of hydrogen bonding.

In DNA, there are four bases guanine(G), adenine(A), cytosine(C) and thymine(T). These bases through hydrogen bonding are associated with there respective bases :adenine is bonded to thymine and guanine is bonded cytosine.

(A=T): Two hydrogen bonds between the bases

(C≡G): Three hydrogen bonds between the bases.

Mamont248 [21]3 years ago

6 0

The structural components that form the rungs of the ladder are the nitrogeneous bases of the DNA molecule. These bases are adenine, guanine, cytosine and thymine. Hope this answers the question. Have a nice day.

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3 years ago

A student puts 0.020 mol of methyl methanoate into an empty and rigid 1.0 L vessel at 450 K. The pressure is measured to be 0.74

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Explanation:

Starting moles of ethanol acid = 0.020 mol

At the equilibrium 50 % of the ethanol acid molecules reacted

∴ Moles of ethanol acid reacted = 0.020 mol * 50 %/100 %

= 0.010 mol

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Moles of the product $(CH3COOH)^{2}$ gas formed are calculated as

0.010 mol CH3COOH * 1 mol $(CH3COOH)^{2}$ / 2 mol CH3COOH

= 0.005 mol $(CH3COOH)^{2}$

Therefore at the equilibrium total moles of gas present in the vessel are 0.010 mol CH3COOH and 0.005 mol $(CH3COOH)^{2}$

That is total gas moles at equilibrium = 0.010 mol + 0.005 mol = 0.015 mol

Now Calculate the pressure :

0.020 mol gas has pressure of 0.74 atm therefore at the same condition what will be the pressure exerted by 0.015 mol gas

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P2 = P1*n2 / n1

= 0.74 atm * 0.015 mol / 0.020 mol

= 0.555 atm

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4 years ago