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3 years ago

The structure of DNA resembles a twisted ladder. Determine the structural components that form the rungs of the ladder.

2 answers:

8 0

Answer: Nitrogenous bases guanine(G), adenine(A), cytosine(C) and thymine(T) forms the rungs of the ladder in twisted ladder structure of DNA.

Explanation:

Rungs of the ladder are normally horizontal small logs placed one after the other with small gaps between them on the two vertically standing logs of the ladder.

Since, DNA resembles the twisted ladder structure the rungs of the ladder structure of DNA are the organic nitrogenous basic molecules which are associated to their respective base with the help of hydrogen bonding.

In DNA, there are four bases guanine(G), adenine(A), cytosine(C) and thymine(T). These bases through hydrogen bonding are associated with there respective bases :adenine is bonded to thymine and guanine is bonded cytosine.

(A=T): Two hydrogen bonds between the bases

(C≡G): Three hydrogen bonds between the bases.

Mamont248 [21]3 years ago

6 0

The structural components that form the rungs of the ladder are the nitrogeneous bases of the DNA molecule. These bases are adenine, guanine, cytosine and thymine. Hope this answers the question. Have a nice day.

You might be interested in

How many moles of NaCl will react completely with 18.5 L F2 gas at 300.0 K and 1.00 atm?

meriva

Hello!

Data:

P (pressure) = 1 atm
V (volume) = 18.5 L
T (temperature) = 300 K
n (number of mols) = ? (in mol)
R (Gas constant) = 0.082 (atm*L/mol*K)

Apply the data to the Clapeyron equation (ideal gas equation), see:
$P*V = n*R*T$

$1*18.5 = n*0.082*300$

$18.5 = 24.6n$

$24.6n = 18.5$

$n = \dfrac{18.5}{24.6}$

$\boxed{\boxed{n \approx 0,752\:mol}}\end{array}}\qquad\checkmark$

Note: If the feedback is to be considered, the closest response is 0.751 mol Nacl

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I hope this helps. =)

3 0

3 years ago

THIS IS DUE TODAY!!!!!!!!!!!!!!!!!!!!!!!!!! PLEASE HELP ME ASAPPPPPPPP CHEMISTRY!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

allochka39001 [22]

Answer:

$\large \boxed{\text{0.1767 mol/L}}$$

Explanation:

(a) Balanced equation

3NaOH + H₃PO₄ ⟶ Na₃PO₄ + 3H₂O

(b) Moles of NaOH

$\text{Moles of NaOH} = \text{34.52 mL NaOH} \times \dfrac{\text{0.3840 mmol NaOH}}{\text{1 mL NaOH}} = \text{13.26 mmol NaOH}$

(c) Moles of H₃PO₄

The molar ratio is 1 mol H₃PO₄:3 mol NaOH.

$\text{Moles of H$_{3}$PO}_{4} = \text{13.26 mmol NaOH} \times\dfrac{\text{ 1 mmol H$_{3}$PO}_{4}}{\text{3 mmol NaOH}}\\\\= \text{4.419 mmol H$_{3}$PO}_{4}$

(d) Molar concentration of H₃PO₄

$c = \dfrac{\text{moles of solute}}{\text{litres of solution}}\\\\c = \dfrac{n}{V} = \dfrac{\text{4.419 mmol}}{\text{25.00 mL}} = \text{0.1767 mol $\cdot$ L$^{-1}$}\\\\\text{The molar concentration of the NaOH is $\large \boxed{\textbf{0.1767 mol/L}}$}$

7 0

3 years ago

1 It was found that 4n atoms of metal x

raketka [301]

Answer:

C 108

Explanation:

1 It was found that 4n atoms of metal x

weigh 501.6 g. The relative atomic mass

of X is 209. If n atoms of another metal,

Y, weigh 65.00 g, what is the relative

atomic mass of metal Y?

A 27 B 52 C 108 D 137

if 4n atoms of x weigh 501.6 gm, the n atoms weigh 501.6/4 = 125.4 gms

since the atomic mass is 209, then 6.022 X10^23 atom weigh 209

the ratio of 125.4 to 209 is

125.4/Y =0.6

therefor n is the number of atom in 0.6 moles

if metal Y has the same, number of atoms "n" and weighs 65 gm

then then the relative atomic mass is

65/0.6 =108

so the answer is

C 108

7 0

2 years ago

What is the amount in moles of a 52 g sample of aluminium fluoride, AIF3

Karo-lina-s [1.5K]

Answer:

Try looking for some kind of answer that has to do with .61904

Explanation:

52 g x 1 mol/ (molar mass of aluminum fluoride) 84 g = .619047619

Sorry if this is wrong but that's my best guess

6 0

3 years ago

Help pleaseeeeee. dbdb

maks197457 [2]

Answer:

no way

Explanation:

more free points

3 0

3 years ago