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Savatey [412]
3 years ago
14

The fulcrum is between the effort and the load

Physics
1 answer:
Inessa05 [86]3 years ago
3 0

Class 1 lever

Explanation:

In a class 1 lever, the fulcrum is placed between the effort and the load. This lever systems is the most common.

  • The effort is the force input and the load is the force output
  • The fulcrum is a hinge between the load and effort.
  • Movement of the effort and load are in opposite directions.
  • There are other classes of lever like the class 2 and 3.
  • They all have different load, fulcrum and effort configurations

learn more:

Load related problems brainly.com/question/9202964

Torque brainly.com/question/5352966

#learnwithBrainly

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The rate which light flows through a given area of space is referred to as ita
Brilliant_brown [7]
Hey there! 

The correct answer to your question is: Intensity

The rate which light flows through a given area of space is referred to as its intensity. I<span>ntensity and wavelength are two factors which contribute to light energy.</span>
Thank you!
7 0
3 years ago
A uniform sphere (I = 2/5 MR 2 ) rolls down an incline. (a) What must be the incline angle if the linear acceleration of the cen
Liono4ka [1.6K]

Answer:

Part a)

\theta = 8.05 degree

Part b)

a = 1.37 m/s^2

Explanation:

As the uniform sphere is rolling down the inclined plane then the net force on the sphere is given as

mg sin\theta - F_f = ma

also we have torque equation on it

F_f R = I\alpha

for pure rolling

a = R \alpha

F_f = \frac{Ia}{R^2}

now we have

mg sin\theta = ma + \frac{Ia}{R^2}

now we have

mg sin\theta = (m + \frac{2}{5}m)a

a = \frac{5}{7}g sin\theta

now given that

a = 0.10 g

so we have

0.10 g = \frac{5}{7} g sin\theta

sin\theta = 0.14

\theta = 8.05 degree

Part b)

If the inclined plane is frictionless then the acceleration is given as

a = g sin\theta

a = 9.8(0.14)

a = 1.37 m/s^2

5 0
3 years ago
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Can someone help me with science:
Oliga [24]

Answer:

trur

Explanation:

gvidttcyhjddgdhjfjdjsjs

6 0
3 years ago
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An unstrained horizontal spring has a length of 0.26 m and a spring constant of 180 N/m. Two small charged objects are attached
MakcuM [25]

Answer:

a)

two like charges always repel each other while two unlike charges attract each other. Since the spring stretches by 0.039 m, the charges have the same sign. both charges are positive(+) or Negative (-)

b)

both q1 and q1 are 8.35 × 10⁻⁶ C or -8.35 × 10⁻⁶ C

Explanation:

Given that;

L = 0.26 m

k = 180 N/m

x = 0.039 m

a)

we know that two like charges always repel each other while two unlike charges attract each other. Since the spring stretches by 0.039 m, the charges have the same sign.

b)

Spring force F = kx

F = 180 × 0.039

F = 7.02 N

Now, Electrostatic force F = Keq²/r²

where r = L + x = ( 0.26 + 0.039 )

we know that proportionality constant in electrostatics equations Ke = 9×10⁹ kg⋅m3⋅s−2⋅C−2

so from the equation; F = Keq²/r²

Fr² = Keq²

q = √ ( Fr² / Ke )

we substitute

q = √ ( 7.02 N × ( 0.26 + 0.039 )² / 9×10⁹ )

q = √ ( 7.02 N × ( 0.26 + 0.039 )² / 9×10⁹ )

q =  √ (0.627595 / 9×10⁹)

q = √(6.97 × 10⁻¹¹)

q = 8.35 × 10⁻⁶ C

Therefore both q1 and q1 are 8.35 × 10⁻⁶ C or -8.35 × 10⁻⁶ C

5 0
3 years ago
Consider a sphere and a cylinder of equal volume made of copper. Both the sphere and the cylinder are initially at the same temp
zepelin [54]

Answer: The cylinder

Explanation:

Among all other solid shapes, the sphere has the smallest area for a given volume.

By experiment, the ratio of the radius of a sphere to a cylinder of equal volume is less than 1.

Recall;

That the Rate of transfer of convective heat (Q) = h × A ×change in temperature.

Where ,

h= the co efficient of convective heat transfer

A= the cross sectional area.

As such, since the sphere has a smaller surface area relative to the cylinder, the sphere transfers heat slower than the cylinder.

Therefore, if the sphere and cylinder are exposed to convection in the same environment, then, the cylinder cools faster.

PS; the more the Area, the higher the rate of heat transfer and vice versa.

7 0
3 years ago
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